The distance between the centers of two circles having radii 9 cm and ...
Since the distance between the centers is 13 cm, they touch each other.
CD is the common tangent
CA = AB and AD = AB [∵ Tangents drawn from a common point are same]
∴ CD = CA + AD = 2AB
⇒ ∠PAC = ∠BAP
⇒ ∠DAQ = ∠BAQ [∵ Line drawn from the center divides the angle between the tangents]
⇒ ∠CAP + ∠PAB + ∠BAQ + ∠DAQ = 180° [Angle is straight line is 180°]
⇒ 2 × (∠PAB + ∠BAQ) = 180°
∴ ∠PAB + ∠BAQ = 90°
⇒ tan∠PAB = PB/AB
⇒ tan∠BAQ = tan(90 - ∠PAB) = cot∠PAB = QB/AB
⇒ tan∠PAB × cot∠PAB = 1
⇒ PB/AB × QB/AB = 1
⇒ 9/AB × 4/AB = 1
⇒ AB2 = 36
∴ AB = 6 cm
∴ CD = 2AB = 12 cm
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The distance between the centers of two circles having radii 9 cm and ...
To find the length of the direct common tangent of two circles, we can use the Pythagorean theorem and the fact that the radii form a right triangle with the length of the direct common tangent as the hypotenuse.
Let's label the centers of the circles as O1 and O2, and the radii as r1 = 9 cm and r2 = 4 cm. The distance between the centers of the circles is given as 13 cm.
- Label the centers of the circles and the radii
- Use the Pythagorean theorem to find the length of the direct common tangent
Using the Pythagorean theorem, we have:
(Length of direct common tangent)^2 = (Distance between centers)^2 - (Sum of radii)^2
Let's substitute the given values into the equation:
(Length of direct common tangent)^2 = (13 cm)^2 - (9 cm + 4 cm)^2
(Length of direct common tangent)^2 = 169 cm^2 - 169 cm^2
(Length of direct common tangent)^2 = 0 cm^2
Since the square of the length of the direct common tangent is 0, it means that the length itself is also 0. This implies that the two circles are touching each other at a single point, and there is no direct common tangent between them.
Therefore, the correct answer is None of the above (0 cm).