A student secure 40% of the marks to pass an examination. He gets only...
Total marks required for passing = 45 + 5 = 50 marks
50 marks is 40% of the maximum marks
⇒ 50 = 40/100 × Maximum marks
∴ Maximum mark = 50 × 100/40 = 125 marks
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A student secure 40% of the marks to pass an examination. He gets only...
(45+5)= 50 is the passing marks as he failed by just 5 marks. Then, let the maximum score be x.
40/100 * x = 50
4x/10 = 50
x = 50*10/4
Therefore, x = 125
A student secure 40% of the marks to pass an examination. He gets only...
To solve this problem, we need to use the given information about the student's marks and the passing criteria. Let's break down the problem into smaller steps:
Step 1: Determine the passing marks
The student secured only 40% of the marks required to pass the examination. Since the student failed by 5 marks, we can calculate the passing marks as follows:
Let the total marks for the examination be 'x'.
40% of x = passing marks
Therefore, 0.4x = passing marks
Step 2: Calculate the passing marks using the given information
According to the question, the student secured only 45 marks and failed by 5 marks. We can use this information to calculate the passing marks:
Passing marks = 45 + 5
Passing marks = 50
Step 3: Solve for 'x' - the total marks for the examination
Now, we can equate the passing marks obtained in Step 2 with the passing marks calculated in Step 1:
0.4x = 50
To solve for 'x', we divide both sides of the equation by 0.4:
x = 50 / 0.4
x = 125
Therefore, the maximum marks for the examination are 125. Hence, the correct answer is option 'B'.
In conclusion, the student secured 45 marks in an examination where the passing marks were 50. To find the maximum marks for the examination, we used the passing criteria (40% of the total marks) and calculated that the maximum marks for the examination were 125.