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What is the positive value of m for which the roots of the equation 12x2 + mx + 5 = 0 are in the ratio 3 ∶ 2?
  • a)
    5 √10
  • b)
    5 √10/12
  • c)
    5/12
  • d)
    12/5
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
What is the positive value of m for which the roots of the equation 12...
Let the roots be 3t and 2t respectively
Product of the roots = c/a
3t × 2t = 5/12
t2 = 5/72
∴ t = ± √5/(6√2)
Sum of roots = -b/a
3t + 2t = -m/12
-60t = m
∴ m = -60 × ± √5/(6√2) = ± 5√10
Only positive value of m is required
∴ m = 5√10
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Most Upvoted Answer
What is the positive value of m for which the roots of the equation 12...
Let the roots of the equation be 3k and 2k, where k is a constant.

By Vieta's formulas, the sum of the roots is given by 3k + 2k = -m/12.

Simplifying, we have 5k = -m/12.

Since we want the roots to be in the ratio 3:2, we can set up the equation 3k/2k = 3/2.

Simplifying, we have 3/2 = 3/2.

Therefore, k = 1.

Substituting this back into the equation 5k = -m/12, we have 5 = -m/12.

Solving for m, we have m = -60.

Since we want the positive value of m, the answer is m = 60.

Therefore, the positive value of m for which the roots of the equation are in the ratio 3:2 is 60.

The correct answer is a) 60.
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