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State the part of the electromagnetic spectrum to which 1057 MHz (frequency of radiation arising from two close energy levels in hydrogen; known as Lamb shift)..Belongs
  • a)
    Visible
  • b)
    Ultraviolet
  • c)
    Microwave
  • d)
    Radio (short wavelength end)
Correct answer is option 'D'. Can you explain this answer?
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State the part of the electromagnetic spectrum to which 1057 MHz (freq...
The Electromagnetic Spectrum and 1057 MHz Radiation

The electromagnetic spectrum is a range of all types of electromagnetic radiation. It includes various forms of energy such as radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. Each of these forms of energy has a specific frequency and wavelength.

1057 MHz is a specific frequency of radiation that is known as the Lamb shift. This radiation arises due to the interaction between an electron and a proton in a hydrogen atom. It is a very low-frequency radiation, and it belongs to the radio wave part of the electromagnetic spectrum.

Therefore, the correct answer to the given question is option D, i.e., radio (short wavelength end).

In summary, the Lamb shift radiation with a frequency of 1057 MHz belongs to the radio wave part of the electromagnetic spectrum.
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State the part of the electromagnetic spectrum to which 1057 MHz (freq...
The frequency of radiation arising from the two close energy levels in hydrogen known as Lamb shift i.e. 1057 MHz is radio waves as it belongs to the short wavelength end of the electromagnetic spectrum. this wavelength correspond to microwave region of electromagnetic waves
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State the part of the electromagnetic spectrum to which 1057 MHz (frequency of radiation arising from two close energy levels in hydrogen; known as Lamb shift)..Belongsa)Visibleb)Ultravioletc)Microwaved)Radio (short wavelength end)Correct answer is option 'D'. Can you explain this answer?
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