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The length of the second’s pendulum on the surface of earth is 1m. The length of second’s pendulum on the surface of moon, where g is 1/6th the value on earth is
  • a)
    6m
  • b)
    1/ 36m
  • c)
    36m
  • d)
    1/ 6m
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The length of the seconds pendulum on the surface of earth is 1m. The ...
Time period remains same since
T = 2π √(L/g)
So, from proportionality we can solve
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Most Upvoted Answer
The length of the seconds pendulum on the surface of earth is 1m. The ...
Time period remains same
T=2π√L/g
so from proportionality we can solve
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