JEE Exam > JEE Questions > An asteroid of mass m (m << mE) is appr...
Start Learning for Free
An asteroid of mass m (m << mE) is approaching with a velocity 12 km/s when it is at distance of 10 R from the centre of earth (where R is radius of earth). When it reaches at the surface of Earth, its velocity is (Nearest Integer) in km/s.
Correct answer is '16'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
An asteroid of mass m (m << mE) is approaching with a velocity 1...
= 16.028 km/s
Most Upvoted Answer
An asteroid of mass m (m << mE) is approaching with a velocity 1...
Unknown) is moving in a circular orbit around a planet of mass M. The radius of the orbit is R. The gravitational force between the asteroid and the planet provides the centripetal force that keeps the asteroid in its orbit.
The gravitational force between two objects can be calculated using the equation:
F = G * (m * M) / r^2
Where F is the gravitational force, G is the gravitational constant, m and M are the masses of the objects, and r is the distance between the objects.
In this case, the gravitational force between the asteroid and the planet is providing the centripetal force. The centripetal force can be calculated using the equation:
F = (m * v^2) / R
Where F is the centripetal force, m is the mass of the asteroid, v is the velocity of the asteroid, and R is the radius of the orbit.
Since the gravitational force provides the centripetal force, we can set the two equations equal to each other:
G * (m * M) / r^2 = (m * v^2) / R
Simplifying the equation, we get:
G * M / r^2 = v^2 / R
Rearranging the equation to solve for v^2, we get:
v^2 = (G * M * R) / r^2
Taking the square root of both sides, we get:
v = √(G * M * R) / r
So, the velocity of the asteroid in its circular orbit is given by:
v = √(G * M * R) / r
The gravitational force between two objects can be calculated using the equation:
F = G * (m * M) / r^2
Where F is the gravitational force, G is the gravitational constant, m and M are the masses of the objects, and r is the distance between the objects.
In this case, the gravitational force between the asteroid and the planet is providing the centripetal force. The centripetal force can be calculated using the equation:
F = (m * v^2) / R
Where F is the centripetal force, m is the mass of the asteroid, v is the velocity of the asteroid, and R is the radius of the orbit.
Since the gravitational force provides the centripetal force, we can set the two equations equal to each other:
G * (m * M) / r^2 = (m * v^2) / R
Simplifying the equation, we get:
G * M / r^2 = v^2 / R
Rearranging the equation to solve for v^2, we get:
v^2 = (G * M * R) / r^2
Taking the square root of both sides, we get:
v = √(G * M * R) / r
So, the velocity of the asteroid in its circular orbit is given by:
v = √(G * M * R) / r
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
An asteroid of mass m (m << mE) is approaching with a velocity 12 km/s when it is at distance of 10 R from the centre of earth (where R is radius of earth). When it reaches at the surface of Earth, its velocity is (Nearest Integer) in km/s.Correct answer is '16'. Can you explain this answer?
Question Description
An asteroid of mass m (m << mE) is approaching with a velocity 12 km/s when it is at distance of 10 R from the centre of earth (where R is radius of earth). When it reaches at the surface of Earth, its velocity is (Nearest Integer) in km/s.Correct answer is '16'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An asteroid of mass m (m << mE) is approaching with a velocity 12 km/s when it is at distance of 10 R from the centre of earth (where R is radius of earth). When it reaches at the surface of Earth, its velocity is (Nearest Integer) in km/s.Correct answer is '16'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An asteroid of mass m (m << mE) is approaching with a velocity 12 km/s when it is at distance of 10 R from the centre of earth (where R is radius of earth). When it reaches at the surface of Earth, its velocity is (Nearest Integer) in km/s.Correct answer is '16'. Can you explain this answer?.
An asteroid of mass m (m << mE) is approaching with a velocity 12 km/s when it is at distance of 10 R from the centre of earth (where R is radius of earth). When it reaches at the surface of Earth, its velocity is (Nearest Integer) in km/s.Correct answer is '16'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An asteroid of mass m (m << mE) is approaching with a velocity 12 km/s when it is at distance of 10 R from the centre of earth (where R is radius of earth). When it reaches at the surface of Earth, its velocity is (Nearest Integer) in km/s.Correct answer is '16'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An asteroid of mass m (m << mE) is approaching with a velocity 12 km/s when it is at distance of 10 R from the centre of earth (where R is radius of earth). When it reaches at the surface of Earth, its velocity is (Nearest Integer) in km/s.Correct answer is '16'. Can you explain this answer?.
Solutions for An asteroid of mass m (m << mE) is approaching with a velocity 12 km/s when it is at distance of 10 R from the centre of earth (where R is radius of earth). When it reaches at the surface of Earth, its velocity is (Nearest Integer) in km/s.Correct answer is '16'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of An asteroid of mass m (m << mE) is approaching with a velocity 12 km/s when it is at distance of 10 R from the centre of earth (where R is radius of earth). When it reaches at the surface of Earth, its velocity is (Nearest Integer) in km/s.Correct answer is '16'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
An asteroid of mass m (m << mE) is approaching with a velocity 12 km/s when it is at distance of 10 R from the centre of earth (where R is radius of earth). When it reaches at the surface of Earth, its velocity is (Nearest Integer) in km/s.Correct answer is '16'. Can you explain this answer?, a detailed solution for An asteroid of mass m (m << mE) is approaching with a velocity 12 km/s when it is at distance of 10 R from the centre of earth (where R is radius of earth). When it reaches at the surface of Earth, its velocity is (Nearest Integer) in km/s.Correct answer is '16'. Can you explain this answer? has been provided alongside types of An asteroid of mass m (m << mE) is approaching with a velocity 12 km/s when it is at distance of 10 R from the centre of earth (where R is radius of earth). When it reaches at the surface of Earth, its velocity is (Nearest Integer) in km/s.Correct answer is '16'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice An asteroid of mass m (m << mE) is approaching with a velocity 12 km/s when it is at distance of 10 R from the centre of earth (where R is radius of earth). When it reaches at the surface of Earth, its velocity is (Nearest Integer) in km/s.Correct answer is '16'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup