Question Description
If electric field around a surface is given bywhere A is the normal area of surface and Qin isthe charge enclosed by the surface. This relation of gausss law is valid whena)Surface is equipotentialb)Magnitude of electric field is constantc)Magnitude of electric field is constant and the surface is equipotentiald)For all Gaussian surfacesCorrect answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If electric field around a surface is given bywhere A is the normal area of surface and Qin isthe charge enclosed by the surface. This relation of gausss law is valid whena)Surface is equipotentialb)Magnitude of electric field is constantc)Magnitude of electric field is constant and the surface is equipotentiald)For all Gaussian surfacesCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If electric field around a surface is given bywhere A is the normal area of surface and Qin isthe charge enclosed by the surface. This relation of gausss law is valid whena)Surface is equipotentialb)Magnitude of electric field is constantc)Magnitude of electric field is constant and the surface is equipotentiald)For all Gaussian surfacesCorrect answer is option 'C'. Can you explain this answer?.

Solutions for If electric field around a surface is given bywhere A is the normal area of surface and Qin isthe charge enclosed by the surface. This relation of gausss law is valid whena)Surface is equipotentialb)Magnitude of electric field is constantc)Magnitude of electric field is constant and the surface is equipotentiald)For all Gaussian surfacesCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of If electric field around a surface is given bywhere A is the normal area of surface and Qin isthe charge enclosed by the surface. This relation of gausss law is valid whena)Surface is equipotentialb)Magnitude of electric field is constantc)Magnitude of electric field is constant and the surface is equipotentiald)For all Gaussian surfacesCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of If electric field around a surface is given bywhere A is the normal area of surface and Qin isthe charge enclosed by the surface. This relation of gausss law is valid whena)Surface is equipotentialb)Magnitude of electric field is constantc)Magnitude of electric field is constant and the surface is equipotentiald)For all Gaussian surfacesCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for If electric field around a surface is given bywhere A is the normal area of surface and Qin isthe charge enclosed by the surface. This relation of gausss law is valid whena)Surface is equipotentialb)Magnitude of electric field is constantc)Magnitude of electric field is constant and the surface is equipotentiald)For all Gaussian surfacesCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of If electric field around a surface is given bywhere A is the normal area of surface and Qin isthe charge enclosed by the surface. This relation of gausss law is valid whena)Surface is equipotentialb)Magnitude of electric field is constantc)Magnitude of electric field is constant and the surface is equipotentiald)For all Gaussian surfacesCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice If electric field around a surface is given bywhere A is the normal area of surface and Qin isthe charge enclosed by the surface. This relation of gausss law is valid whena)Surface is equipotentialb)Magnitude of electric field is constantc)Magnitude of electric field is constant and the surface is equipotentiald)For all Gaussian surfacesCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.