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A person distributes his pens among four friends A, B, C and D in the ratio 1/3 : 1 / 4 : 1/5 : 1/6. What is the minimum number of pens that the person should have ?
  • a)
    57
  • b)
    48
  • c)
    62
  • d)
    38
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A person distributes his pens among four friends A, B, C and D in the ...
Ratio among A, B, C and D = 
= 20 : 15 : 12 : 10
So, minimum  number of pens = 20 + 15 + 12 +10 = 57
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Most Upvoted Answer
A person distributes his pens among four friends A, B, C and D in the ...
Solution:

Given, the ratio of distribution of pens among A, B, C, and D is 1/3 : 1/4 : 1/5 : 1/6.

Let the common ratio be x. Then,

1/3x + 1/4x + 1/5x + 1/6x = 1

LCM of 3, 4, 5, and 6 is 60.

20 + 15 + 12 + 10 = 60

57x/60 = 1

x = 60/57

Therefore, the minimum number of pens that the person should have = (1 + 1 + 1 + 1) x (60/57) = 60/57 x 4 = 4.21 x 4 = 16.84

Since the person cannot have a fraction of a pen, the minimum number of pens to be distributed should be the next highest integer, which is 17.

Hence, the correct answer is option A, 57.
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