In a cross CcDdEe × ccddEe what will be the probability of organism wh...
Solution:
Given cross is CcDdEe × ccddEe.
Possible gametes of CcDdEe are CD, Cd, cD, cd, DE, De, dE, and de.
Possible gametes of ccddEe are cde and Cde.
Therefore, the possible genotypes of the offspring are CCDdEe, CcDdEe, CCDdee, CcDdee, ccDdEe, ccDdee, ccddEe, and ccddEE.
To find the probability of offspring being homozygous for the first character (CC), heterozygous for the second character (Dd), and heterozygous for the third character (Ee), we need to look at the possible genotypes and count how many of them fit this description.
The only genotype that matches this description is CCDdEe.
Therefore, the probability of an offspring being homozygous for the first character (CC), heterozygous for the second character (Dd), and heterozygous for the third character (Ee) is 1/8.
Answer: The probability of an organism being homozygous for the first character (CC), heterozygous for the second character (Dd), and heterozygous for the third character (Ee) is 1/8.
In a cross CcDdEe × ccddEe what will be the probability of organism wh...
The answer is (1/8)