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Let 0 < θ < π/2. If the eccentricity of the hyperbola  is greater than 2, then the length of its latus rectum lies in the interval :
  • a)
    (2, 3]
  • b)
    (3, ∞)
  • c)
    (3/2, 2]
  • d)
    (1, 3/2]
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Let 0 < θ <π/2.If the eccentricity of thehyperbolais gr...


=2(sec θ – cos θ)
Which is strictly increasing, so
ℓ (L.R) ∈(3, ∞).
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Let 0 < θ <π/2.If the eccentricity of thehyperbolais greater than 2,then the length of its latus rectum lies in the interval :a)(2, 3]b)(3, ∞)c)(3/2, 2]d)(1, 3/2]Correct answer is option 'B'. Can you explain this answer?
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Let 0 < θ <π/2.If the eccentricity of thehyperbolais greater than 2,then the length of its latus rectum lies in the interval :a)(2, 3]b)(3, ∞)c)(3/2, 2]d)(1, 3/2]Correct answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Let 0 < θ <π/2.If the eccentricity of thehyperbolais greater than 2,then the length of its latus rectum lies in the interval :a)(2, 3]b)(3, ∞)c)(3/2, 2]d)(1, 3/2]Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let 0 < θ <π/2.If the eccentricity of thehyperbolais greater than 2,then the length of its latus rectum lies in the interval :a)(2, 3]b)(3, ∞)c)(3/2, 2]d)(1, 3/2]Correct answer is option 'B'. Can you explain this answer?.
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