Class 12 Exam > Class 12 Questions > You have a special light bulb with a very del...
Start Learning for Free
You have a special light bulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.50 A, even for an instant. What is the largest root-mean-square current you can run through this bulb?
- a)1.46 A
- b)1.06 A
- c)1.26 A
- d)1.56 A
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
You have a special light bulb with a very delicate wire filament. The ...
Given,
We are given the current I=1.5Am where the wire will break.
We are asked to determine the root mean square of the current Irms. The maximum current here represents the current that just after it the wire will break. The maximum value of the current is the amplitude of the current wave and it should be larger than the root mean square of the current. Using equation, we can get the Irms in the form,
Irms = Imax/√2
The term, 1/√2, times any factor represents the root mean square of this factor, Now, plug the value for Imax into equation 1 and get Irms
Irms=Imax/√2
=1.5A/√2
=1.06A.
We are given the current I=1.5Am where the wire will break.
We are asked to determine the root mean square of the current Irms. The maximum current here represents the current that just after it the wire will break. The maximum value of the current is the amplitude of the current wave and it should be larger than the root mean square of the current. Using equation, we can get the Irms in the form,
Irms = Imax/√2
The term, 1/√2, times any factor represents the root mean square of this factor, Now, plug the value for Imax into equation 1 and get Irms
Irms=Imax/√2
=1.5A/√2
=1.06A.
Most Upvoted Answer
You have a special light bulb with a very delicate wire filament. The ...
Problem Analysis:
We need to determine the largest root-mean-square current that can be run through the light bulb without breaking the delicate wire filament. The wire will break if the current exceeds 1.50 A, even for an instant. We can use the equation for root-mean-square (rms) current to solve this problem.
Solution:
To find the largest root-mean-square current that can be run through the light bulb, we need to find the maximum current that does not exceed 1.50 A.
Root-Mean-Square Current:
The root-mean-square (rms) current, denoted as Irms, is the value of the current that, when squared and averaged over time, gives the same power as the corresponding alternating current (AC).
Formula:
The formula for root-mean-square (rms) current is given by:
Irms = Imax / √2
Where,
Irms is the root-mean-square (rms) current,
Imax is the maximum current.
Calculating the largest root-mean-square current:
Given that the wire filament will break if the current exceeds 1.50 A, even for an instant, we can set the maximum current (Imax) equal to this value.
Imax = 1.50 A
Using the formula for root-mean-square (rms) current, we can calculate the largest root-mean-square current as follows:
Irms = Imax / √2
Irms = 1.50 A / √2
Irms ≈ 1.06 A
Therefore, the largest root-mean-square current that can be run through the light bulb without breaking the delicate wire filament is approximately 1.06 A.
We need to determine the largest root-mean-square current that can be run through the light bulb without breaking the delicate wire filament. The wire will break if the current exceeds 1.50 A, even for an instant. We can use the equation for root-mean-square (rms) current to solve this problem.
Solution:
To find the largest root-mean-square current that can be run through the light bulb, we need to find the maximum current that does not exceed 1.50 A.
Root-Mean-Square Current:
The root-mean-square (rms) current, denoted as Irms, is the value of the current that, when squared and averaged over time, gives the same power as the corresponding alternating current (AC).
Formula:
The formula for root-mean-square (rms) current is given by:
Irms = Imax / √2
Where,
Irms is the root-mean-square (rms) current,
Imax is the maximum current.
Calculating the largest root-mean-square current:
Given that the wire filament will break if the current exceeds 1.50 A, even for an instant, we can set the maximum current (Imax) equal to this value.
Imax = 1.50 A
Using the formula for root-mean-square (rms) current, we can calculate the largest root-mean-square current as follows:
Irms = Imax / √2
Irms = 1.50 A / √2
Irms ≈ 1.06 A
Therefore, the largest root-mean-square current that can be run through the light bulb without breaking the delicate wire filament is approximately 1.06 A.
Free Test
FREE
| Start Free Test |
Community Answer
You have a special light bulb with a very delicate wire filament. The ...
I(r.m.s.)=I/√2
=1.5/1.14
=1.5/1.14
|
Explore Courses for Class 12 exam
|
|
Similar Class 12 Doubts
You have a special light bulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.50 A, even for an instant. What is the largest root-mean-square current you can run through this bulb?a)1.46 Ab)1.06 Ac)1.26 Ad)1.56 ACorrect answer is option 'B'. Can you explain this answer?
Question Description
You have a special light bulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.50 A, even for an instant. What is the largest root-mean-square current you can run through this bulb?a)1.46 Ab)1.06 Ac)1.26 Ad)1.56 ACorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about You have a special light bulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.50 A, even for an instant. What is the largest root-mean-square current you can run through this bulb?a)1.46 Ab)1.06 Ac)1.26 Ad)1.56 ACorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for You have a special light bulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.50 A, even for an instant. What is the largest root-mean-square current you can run through this bulb?a)1.46 Ab)1.06 Ac)1.26 Ad)1.56 ACorrect answer is option 'B'. Can you explain this answer?.
You have a special light bulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.50 A, even for an instant. What is the largest root-mean-square current you can run through this bulb?a)1.46 Ab)1.06 Ac)1.26 Ad)1.56 ACorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about You have a special light bulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.50 A, even for an instant. What is the largest root-mean-square current you can run through this bulb?a)1.46 Ab)1.06 Ac)1.26 Ad)1.56 ACorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for You have a special light bulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.50 A, even for an instant. What is the largest root-mean-square current you can run through this bulb?a)1.46 Ab)1.06 Ac)1.26 Ad)1.56 ACorrect answer is option 'B'. Can you explain this answer?.
Solutions for You have a special light bulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.50 A, even for an instant. What is the largest root-mean-square current you can run through this bulb?a)1.46 Ab)1.06 Ac)1.26 Ad)1.56 ACorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of You have a special light bulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.50 A, even for an instant. What is the largest root-mean-square current you can run through this bulb?a)1.46 Ab)1.06 Ac)1.26 Ad)1.56 ACorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
You have a special light bulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.50 A, even for an instant. What is the largest root-mean-square current you can run through this bulb?a)1.46 Ab)1.06 Ac)1.26 Ad)1.56 ACorrect answer is option 'B'. Can you explain this answer?, a detailed solution for You have a special light bulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.50 A, even for an instant. What is the largest root-mean-square current you can run through this bulb?a)1.46 Ab)1.06 Ac)1.26 Ad)1.56 ACorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of You have a special light bulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.50 A, even for an instant. What is the largest root-mean-square current you can run through this bulb?a)1.46 Ab)1.06 Ac)1.26 Ad)1.56 ACorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice You have a special light bulb with a very delicate wire filament. The wire will break if the current in it ever exceeds 1.50 A, even for an instant. What is the largest root-mean-square current you can run through this bulb?a)1.46 Ab)1.06 Ac)1.26 Ad)1.56 ACorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 12 tests.
|
|
Explore Courses for Class 12 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup