The number of ways in which 6 men and 5 women can dine at a round tabl...
No. of ways in which 6 men can be arranged at a round table = (6 - 1)! = 5!
Now women can be arranged in 6 P5 = 6! Ways.
Total Number of ways = 6! × 5!
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The number of ways in which 6 men and 5 women can dine at a round tabl...
We can use the concept of circular permutations to solve this problem. Since the table is round, we can fix one person (say a man) at one position and arrange the rest of the people around him. This can be done in (10-1)! = 9! ways.
Now, we need to ensure that no two women sit together. We can first arrange the 6 men in the 6 available seats, which can be done in 6! ways. Then, we can insert the 5 women in the 7 available gaps between the men, such that no two women sit together. This can be done in the following way:
_M_M_M_M_M_M_
We have 7 gaps (marked by underscores) where we can insert the women. We can choose 5 of these gaps for the women in 7C5 = 21 ways. Once we have chosen the gaps, we can arrange the women in them in 5! ways. Therefore, the total number of ways in which the people can be seated is:
9! * 6! * 21 * 5! = 907,200
Therefore, the correct answer is (d) 907,200.