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The number of ways in which 6 men and 5 women can dine at a round table  if no two women   are to sit together is given by[2003]
  • a)
    7! × 5!
  • b)
    6! × 5!
  • c)
    30!
  • d)
    5! × 4!
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The number of ways in which 6 men and 5 women can dine at a round tabl...
No. of ways in which 6 men can be arranged at a round table = (6 - 1)! = 5!
Now women can be arranged in 6 P5 = 6! Ways.
Total Number  of ways  = 6! × 5!
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Most Upvoted Answer
The number of ways in which 6 men and 5 women can dine at a round tabl...
We can use the concept of circular permutations to solve this problem. Since the table is round, we can fix one person (say a man) at one position and arrange the rest of the people around him. This can be done in (10-1)! = 9! ways.

Now, we need to ensure that no two women sit together. We can first arrange the 6 men in the 6 available seats, which can be done in 6! ways. Then, we can insert the 5 women in the 7 available gaps between the men, such that no two women sit together. This can be done in the following way:

_M_M_M_M_M_M_

We have 7 gaps (marked by underscores) where we can insert the women. We can choose 5 of these gaps for the women in 7C5 = 21 ways. Once we have chosen the gaps, we can arrange the women in them in 5! ways. Therefore, the total number of ways in which the people can be seated is:

9! * 6! * 21 * 5! = 907,200

Therefore, the correct answer is (d) 907,200.
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The number of ways in which 6 men and 5 women can dine at a round table if no two women are to sit together is given by[2003]a)7! × 5!b)6! × 5!c)30!d)5! × 4!Correct answer is option 'B'. Can you explain this answer?
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