Eight chairs are numbered 1 to 8. Two women and three men wish to occu...
Two women can choose two chairs in 4C2 ways and arranged in factorial 2 .
After this no.of chairs left =6
3 men can choose 3 chairs out of 6 chairs in 6C3 and arranged in factorial 3.
therefore, required answer = 4P2 × 6P3
Eight chairs are numbered 1 to 8. Two women and three men wish to occu...
Let's break down the problem step by step:
Step 1: Women choose chairs
There are 8 chairs in total, numbered from 1 to 8. The women can only choose chairs from the set {1, 2, 3, 4}. Since there are 2 women and 4 chairs available for them, the number of ways they can choose their chairs is given by the combination formula:
C(4, 2) = 4! / (2! * (4-2)!) = 6
So there are 6 possible ways for the women to choose their chairs.
Step 2: Men choose chairs
After the women have chosen their chairs, there are 4 chairs remaining for the men to choose from, numbered {5, 6, 7, 8}. There are 3 men and 4 chairs available for them, so the number of ways they can choose their chairs is given by the permutation formula:
P(4, 3) = 4! / (4-3)! = 4! / 1! = 4 * 3 * 2 = 24
So there are 24 possible ways for the men to choose their chairs.
Step 3: Total number of arrangements
To find the total number of arrangements, we need to multiply the number of ways the women can choose their chairs (6) by the number of ways the men can choose their chairs (24):
Total arrangements = 6 * 24 = 144
However, the question asks for the number of possible arrangements based on the equation (1982 - 2 Marks). Since the answer choices do not match the value obtained (144), none of the options provided (a, b, c, d) can be correct. Therefore, the correct answer is none of these (option d).