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If α ≠ β but α2 = 5α – 3 and β2 = 5β – 3 then the equation having α/β and β/α as its roots is [2002]
- a)3x2 – 19x + 3 = 0
- b)3x2 + 19x – 3 = 0
- c)3x2 – 19x – 3 = 0
- d)x2 – 5x + 3 = 0.
Correct answer is option 'A'. Can you explain this answer?
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Ifα ≠ β but α2 = 5α – 3 and β2 = ...
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Ifα ≠ β but α2 = 5α – 3 and β2 = ...
Given, a^2 - 5a + 3 = 0 & b^2 - 5b +3 = 0
i.e, X^2 - 5X + 3 =0 has it's roots as "a" & "b".
sum of roots = a + b = 5 and ,
product of roots = ab = 3
a^2 + b^2 = (a + b)^2 - 2ab = 25 - 6 = 19
also, given a/b , b/a are roots of any equation
a/b + b/a = (a^2 + b^2)/ab = 19/3
and required equation will be given by
X^2 - (sum of roots)X + product of roots = 0
X^2 - (a/b + b/a)X + (a/b) × (b/a) = 0
X^2 - (19/3)X + 1 = 0
3X^2 - 19X + 3 = 0
i.e, X^2 - 5X + 3 =0 has it's roots as "a" & "b".
sum of roots = a + b = 5 and ,
product of roots = ab = 3
a^2 + b^2 = (a + b)^2 - 2ab = 25 - 6 = 19
also, given a/b , b/a are roots of any equation
a/b + b/a = (a^2 + b^2)/ab = 19/3
and required equation will be given by
X^2 - (sum of roots)X + product of roots = 0
X^2 - (a/b + b/a)X + (a/b) × (b/a) = 0
X^2 - (19/3)X + 1 = 0
3X^2 - 19X + 3 = 0
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Ifα ≠ β but α2 = 5α – 3 and β2 = 5β – 3 then the equation having α/β and β/α as its roots is [2002]a)3x2 – 19x + 3 = 0b)3x2 + 19x – 3 = 0c)3x2 – 19x – 3 = 0d)x2 – 5x + 3 = 0.Correct answer is option 'A'. Can you explain this answer?
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Ifα ≠ β but α2 = 5α – 3 and β2 = 5β – 3 then the equation having α/β and β/α as its roots is [2002]a)3x2 – 19x + 3 = 0b)3x2 + 19x – 3 = 0c)3x2 – 19x – 3 = 0d)x2 – 5x + 3 = 0.Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Ifα ≠ β but α2 = 5α – 3 and β2 = 5β – 3 then the equation having α/β and β/α as its roots is [2002]a)3x2 – 19x + 3 = 0b)3x2 + 19x – 3 = 0c)3x2 – 19x – 3 = 0d)x2 – 5x + 3 = 0.Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ifα ≠ β but α2 = 5α – 3 and β2 = 5β – 3 then the equation having α/β and β/α as its roots is [2002]a)3x2 – 19x + 3 = 0b)3x2 + 19x – 3 = 0c)3x2 – 19x – 3 = 0d)x2 – 5x + 3 = 0.Correct answer is option 'A'. Can you explain this answer?.
Ifα ≠ β but α2 = 5α – 3 and β2 = 5β – 3 then the equation having α/β and β/α as its roots is [2002]a)3x2 – 19x + 3 = 0b)3x2 + 19x – 3 = 0c)3x2 – 19x – 3 = 0d)x2 – 5x + 3 = 0.Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Ifα ≠ β but α2 = 5α – 3 and β2 = 5β – 3 then the equation having α/β and β/α as its roots is [2002]a)3x2 – 19x + 3 = 0b)3x2 + 19x – 3 = 0c)3x2 – 19x – 3 = 0d)x2 – 5x + 3 = 0.Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ifα ≠ β but α2 = 5α – 3 and β2 = 5β – 3 then the equation having α/β and β/α as its roots is [2002]a)3x2 – 19x + 3 = 0b)3x2 + 19x – 3 = 0c)3x2 – 19x – 3 = 0d)x2 – 5x + 3 = 0.Correct answer is option 'A'. Can you explain this answer?.
Solutions for Ifα ≠ β but α2 = 5α – 3 and β2 = 5β – 3 then the equation having α/β and β/α as its roots is [2002]a)3x2 – 19x + 3 = 0b)3x2 + 19x – 3 = 0c)3x2 – 19x – 3 = 0d)x2 – 5x + 3 = 0.Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Ifα ≠ β but α2 = 5α – 3 and β2 = 5β – 3 then the equation having α/β and β/α as its roots is [2002]a)3x2 – 19x + 3 = 0b)3x2 + 19x – 3 = 0c)3x2 – 19x – 3 = 0d)x2 – 5x + 3 = 0.Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Ifα ≠ β but α2 = 5α – 3 and β2 = 5β – 3 then the equation having α/β and β/α as its roots is [2002]a)3x2 – 19x + 3 = 0b)3x2 + 19x – 3 = 0c)3x2 – 19x – 3 = 0d)x2 – 5x + 3 = 0.Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Ifα ≠ β but α2 = 5α – 3 and β2 = 5β – 3 then the equation having α/β and β/α as its roots is [2002]a)3x2 – 19x + 3 = 0b)3x2 + 19x – 3 = 0c)3x2 – 19x – 3 = 0d)x2 – 5x + 3 = 0.Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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