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The molecular mass of sulphuric acid is 98. If 49 g of the acid is dissolved in water to make one litre of solution, what will be the strength of the acid?
- a)Two normal
- b)One normal
- c)0.5 normal
- d)Four normal
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
The molecular mass of sulphuric acid is 98. If 49 g of the acid is dis...
- Normality (N) - gram - equivalent of solute dissolved in one litre (or one cubic decimetre) of solution.
- Equivalent weight of sulphuric acid = Molecular weight/Valance = 98/2 = 49
- Gram Equivalent of sulphuric acid = Given Mass/ Equivalent weight of sulphuric acid = 49/49 = 1
- Normality = equivalent mass /litre of solution = 1/1 = 1
- Hence answer is One Normal.
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The molecular mass of sulphuric acid is 98. If 49 g of the acid is dis...
The Strength of Sulphuric Acid Solution
To determine the strength of the sulphuric acid solution, we need to calculate its normality. Normality is defined as the number of equivalents of a solute present in one liter of solution.
Step 1: Calculate the number of moles of sulphuric acid present in the solution.
Given that the molecular mass of sulphuric acid is 98 g/mol and 49 g of the acid is dissolved in water, we can use the formula:
Number of moles (n) = Mass (m) / Molecular mass (M)
Number of moles of sulphuric acid = 49 g / 98 g/mol = 0.5 mol
Step 2: Calculate the number of equivalents of sulphuric acid.
Sulphuric acid is a diprotic acid, meaning it can donate two protons (H+) per molecule. Therefore, the number of equivalents is twice the number of moles.
Number of equivalents (N) = 2 * Number of moles (n)
Number of equivalents of sulphuric acid = 2 * 0.5 mol = 1 eq
Step 3: Calculate the normality of the solution.
Normality (N) is defined as the number of equivalents of solute per liter of solution.
Normality (N) = Number of equivalents (N) / Volume of solution (V)
Given that the volume of the solution is 1 liter, we can substitute the values to find the normality.
Normality of the sulphuric acid solution = 1 eq / 1 L = 1 N
Therefore, the strength of the sulphuric acid solution is 1 normal (1N).
To determine the strength of the sulphuric acid solution, we need to calculate its normality. Normality is defined as the number of equivalents of a solute present in one liter of solution.
Step 1: Calculate the number of moles of sulphuric acid present in the solution.
Given that the molecular mass of sulphuric acid is 98 g/mol and 49 g of the acid is dissolved in water, we can use the formula:
Number of moles (n) = Mass (m) / Molecular mass (M)
Number of moles of sulphuric acid = 49 g / 98 g/mol = 0.5 mol
Step 2: Calculate the number of equivalents of sulphuric acid.
Sulphuric acid is a diprotic acid, meaning it can donate two protons (H+) per molecule. Therefore, the number of equivalents is twice the number of moles.
Number of equivalents (N) = 2 * Number of moles (n)
Number of equivalents of sulphuric acid = 2 * 0.5 mol = 1 eq
Step 3: Calculate the normality of the solution.
Normality (N) is defined as the number of equivalents of solute per liter of solution.
Normality (N) = Number of equivalents (N) / Volume of solution (V)
Given that the volume of the solution is 1 liter, we can substitute the values to find the normality.
Normality of the sulphuric acid solution = 1 eq / 1 L = 1 N
Therefore, the strength of the sulphuric acid solution is 1 normal (1N).
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The molecular mass of sulphuric acid is 98. If 49 g of the acid is dissolved in water to make one litre of solution, what will be the strength of the acid?a)Two normalb)One normalc)0.5 normald)Four normalCorrect answer is option 'B'. Can you explain this answer?
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