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A parallel-plate capacitor, with air in between the plates, has capacitance C. Now the space between the two plates of the capacitor is filled with a dielectric of dielectric constant 7. Then the value of the capacitance will become
- a)C
- b)C/7
- c)7C
- d)14C
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A parallel-plate capacitor, with air in between the plates, has capaci...
- Parallel Plate Capacitors are the type of capacitors which are formed by arrangement of two or more parallel conductive plates which are not connected or touching each other but are electrically separated either by air or by some form of a good insulating material.
- Capacitance is directly proportional to value of dielectric constant. Hence Capacitance will be 7C.
Most Upvoted Answer
A parallel-plate capacitor, with air in between the plates, has capaci...
Explanation:
When a dielectric material is inserted between the plates of a capacitor, it affects the capacitance of the capacitor. The presence of a dielectric material increases the capacitance of the capacitor. The relationship between the capacitance with and without a dielectric is given by:
C = κC₀
Where:
C is the capacitance with the dielectric
C₀ is the capacitance without the dielectric
κ is the dielectric constant of the material
In this case, the dielectric constant of air is 1, and the dielectric constant of the material inserted between the plates is 7. Therefore, the relationship becomes:
C = 7C₀
This means that the capacitance with the dielectric is 7 times the capacitance without the dielectric. Since the initial capacitance C is given, the new capacitance after inserting the dielectric becomes:
C' = 7C
Hence, the correct answer is option C, 7C.
When a dielectric material is inserted between the plates of a capacitor, it affects the capacitance of the capacitor. The presence of a dielectric material increases the capacitance of the capacitor. The relationship between the capacitance with and without a dielectric is given by:
C = κC₀
Where:
C is the capacitance with the dielectric
C₀ is the capacitance without the dielectric
κ is the dielectric constant of the material
In this case, the dielectric constant of air is 1, and the dielectric constant of the material inserted between the plates is 7. Therefore, the relationship becomes:
C = 7C₀
This means that the capacitance with the dielectric is 7 times the capacitance without the dielectric. Since the initial capacitance C is given, the new capacitance after inserting the dielectric becomes:
C' = 7C
Hence, the correct answer is option C, 7C.
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