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In a triangle ABC, angle A is greater than angle B. If the measures of angles A and B satisfy the equation 3 sin x – 4 sin3x – k = 0, 0 < k < 1, then the measure of angle C is
  • a)
    π/3
  • b)
    π/2
  • c)
    2π/3
  • d)
    5π/6
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
In a triangle ABC, angle A is greater than angle B. If the measures of...
Given that A > B and 3 sin x – 4 sin 3 x – k = 0, 0 <  k < 1
⇒ sin 3 x = k
As A and B satisfy above eq. (given)
∴ sin 3A = k,  sin 3B = k
⇒ sin 3A – sin 3B = 0

⇒ A + B = 60°  or  A = B
But given that A  >  B,   ∴  A ≠ B
Thus, A + B = 60°
But A + B + C = 180°  ⇒ C = 180° –  60° =  120°
∴ C = 2π3
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Most Upvoted Answer
In a triangle ABC, angle A is greater than angle B. If the measures of...
The equation you provided is incomplete. Could you please provide the complete equation for the measures of angles A and B?
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In a triangle ABC, angle A is greater than angle B. If the measures of angles A and B satisfy the equation 3 sin x – 4 sin3x – k = 0, 0 < k < 1, then the measure of angle C isa)π/3b)π/2c)2π/3d)5π/6Correct answer is option 'C'. Can you explain this answer?
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