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The equivalent conductance of two strong electrolytes at infinite dilution in H2O (where ions move freely through a solution) at 25ºC are given below -
^°CH3COONa= 91.0 S cm2/equiv
^ºHCl = 426.2 S cm2/equiv
What additional information/quantity one needs to calculate Lº of an aqueous solution of acetic acid ?
[AIEEE 2007]
- a)^º of NaCl
- b)^º of CH3COOH
- c)The limiting equivalent conductance of H+(λ°H+)
- d)^º of chloroacetic acid (ClCH2COOH)
Correct answer is option 'A'. Can you explain this answer?
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The equivalent conductance of two strong electrolytes at infinite dilu...
°C is given by the sum of the conductances of their respective cations and anions. The equation for calculating equivalent conductance (Λ) is:
Λ = (λ+ + λ−) × 10^-4 S cm^2 mol^-1
where λ+ is the conductance of the cation and λ− is the conductance of the anion.
For example, the equivalent conductance of NaCl at infinite dilution is:
ΛNaCl = (λNa+ + λCl−) × 10^-4 S cm^2 mol^-1
The conductance of Na+ and Cl- can be found in tables or calculated using the Kohlrausch's law. At infinite dilution, the conductance values are:
λNa+ = 50.1 S cm^2 mol^-1
λCl- = 76.3 S cm^2 mol^-1
Therefore, the equivalent conductance of NaCl at infinite dilution is:
ΛNaCl = (50.1 + 76.3) × 10^-4 S cm^2 mol^-1
ΛNaCl = 0.1264 S cm^2 mol^-1
Similarly, the equivalent conductance of KBr at infinite dilution is:
ΛKBr = (λK+ + λBr−) × 10^-4 S cm^2 mol^-1
At infinite dilution, the conductance values are:
λK+ = 73.5 S cm^2 mol^-1
λBr- = 81.0 S cm^2 mol^-1
Therefore, the equivalent conductance of KBr at infinite dilution is:
ΛKBr = (73.5 + 81.0) × 10^-4 S cm^2 mol^-1
ΛKBr = 0.1545 S cm^2 mol^-1
Λ = (λ+ + λ−) × 10^-4 S cm^2 mol^-1
where λ+ is the conductance of the cation and λ− is the conductance of the anion.
For example, the equivalent conductance of NaCl at infinite dilution is:
ΛNaCl = (λNa+ + λCl−) × 10^-4 S cm^2 mol^-1
The conductance of Na+ and Cl- can be found in tables or calculated using the Kohlrausch's law. At infinite dilution, the conductance values are:
λNa+ = 50.1 S cm^2 mol^-1
λCl- = 76.3 S cm^2 mol^-1
Therefore, the equivalent conductance of NaCl at infinite dilution is:
ΛNaCl = (50.1 + 76.3) × 10^-4 S cm^2 mol^-1
ΛNaCl = 0.1264 S cm^2 mol^-1
Similarly, the equivalent conductance of KBr at infinite dilution is:
ΛKBr = (λK+ + λBr−) × 10^-4 S cm^2 mol^-1
At infinite dilution, the conductance values are:
λK+ = 73.5 S cm^2 mol^-1
λBr- = 81.0 S cm^2 mol^-1
Therefore, the equivalent conductance of KBr at infinite dilution is:
ΛKBr = (73.5 + 81.0) × 10^-4 S cm^2 mol^-1
ΛKBr = 0.1545 S cm^2 mol^-1
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The equivalent conductance of two strong electrolytes at infinite dilu...
For finding the equivalence conductance of ch3cooh there should be given equivalence conductance of NaCl
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The equivalent conductance of two strong electrolytes at infinite dilution in H2O (where ions move freely through a solution) at 25ºC are given below -^°CH3COONa= 91.0 S cm2/equiv^ºHCl = 426.2 S cm2/equivWhat additional information/quantity one needs to calculate Lº of an aqueous solution of acetic acid ?[AIEEE 2007]a)^º of NaClb)^º of CH3COOHc)The limiting equivalent conductance of H+(λ°H+)d)^º of chloroacetic acid (ClCH2COOH)Correct answer is option 'A'. Can you explain this answer?
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The equivalent conductance of two strong electrolytes at infinite dilution in H2O (where ions move freely through a solution) at 25ºC are given below -^°CH3COONa= 91.0 S cm2/equiv^ºHCl = 426.2 S cm2/equivWhat additional information/quantity one needs to calculate Lº of an aqueous solution of acetic acid ?[AIEEE 2007]a)^º of NaClb)^º of CH3COOHc)The limiting equivalent conductance of H+(λ°H+)d)^º of chloroacetic acid (ClCH2COOH)Correct answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The equivalent conductance of two strong electrolytes at infinite dilution in H2O (where ions move freely through a solution) at 25ºC are given below -^°CH3COONa= 91.0 S cm2/equiv^ºHCl = 426.2 S cm2/equivWhat additional information/quantity one needs to calculate Lº of an aqueous solution of acetic acid ?[AIEEE 2007]a)^º of NaClb)^º of CH3COOHc)The limiting equivalent conductance of H+(λ°H+)d)^º of chloroacetic acid (ClCH2COOH)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The equivalent conductance of two strong electrolytes at infinite dilution in H2O (where ions move freely through a solution) at 25ºC are given below -^°CH3COONa= 91.0 S cm2/equiv^ºHCl = 426.2 S cm2/equivWhat additional information/quantity one needs to calculate Lº of an aqueous solution of acetic acid ?[AIEEE 2007]a)^º of NaClb)^º of CH3COOHc)The limiting equivalent conductance of H+(λ°H+)d)^º of chloroacetic acid (ClCH2COOH)Correct answer is option 'A'. Can you explain this answer?.
The equivalent conductance of two strong electrolytes at infinite dilution in H2O (where ions move freely through a solution) at 25ºC are given below -^°CH3COONa= 91.0 S cm2/equiv^ºHCl = 426.2 S cm2/equivWhat additional information/quantity one needs to calculate Lº of an aqueous solution of acetic acid ?[AIEEE 2007]a)^º of NaClb)^º of CH3COOHc)The limiting equivalent conductance of H+(λ°H+)d)^º of chloroacetic acid (ClCH2COOH)Correct answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The equivalent conductance of two strong electrolytes at infinite dilution in H2O (where ions move freely through a solution) at 25ºC are given below -^°CH3COONa= 91.0 S cm2/equiv^ºHCl = 426.2 S cm2/equivWhat additional information/quantity one needs to calculate Lº of an aqueous solution of acetic acid ?[AIEEE 2007]a)^º of NaClb)^º of CH3COOHc)The limiting equivalent conductance of H+(λ°H+)d)^º of chloroacetic acid (ClCH2COOH)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The equivalent conductance of two strong electrolytes at infinite dilution in H2O (where ions move freely through a solution) at 25ºC are given below -^°CH3COONa= 91.0 S cm2/equiv^ºHCl = 426.2 S cm2/equivWhat additional information/quantity one needs to calculate Lº of an aqueous solution of acetic acid ?[AIEEE 2007]a)^º of NaClb)^º of CH3COOHc)The limiting equivalent conductance of H+(λ°H+)d)^º of chloroacetic acid (ClCH2COOH)Correct answer is option 'A'. Can you explain this answer?.
Solutions for The equivalent conductance of two strong electrolytes at infinite dilution in H2O (where ions move freely through a solution) at 25ºC are given below -^°CH3COONa= 91.0 S cm2/equiv^ºHCl = 426.2 S cm2/equivWhat additional information/quantity one needs to calculate Lº of an aqueous solution of acetic acid ?[AIEEE 2007]a)^º of NaClb)^º of CH3COOHc)The limiting equivalent conductance of H+(λ°H+)d)^º of chloroacetic acid (ClCH2COOH)Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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