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Let y be an implicit function of x defined by  x2x – 2xx cot y – 1= 0. Then y'(1) equals
  • a)
    1
  • b)
    log 2
  • c)
    –log 2
  • d)
    –1
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Let y be an implicit function of x defined by x2x – 2xx cot y &n...
x2x – 2xx cot y – 1 = 0
⇒ 2 cot y = xx –  x – x ⇒ 2 cot y =
Differentiating both sides with respect to x, we get

where u = xx ⇒ log u = x log x


Now when x  = 1, x2x – 2xx cot y – 1 = 0, gives
1 – 2 cot y – 1 = 0 ⇒ cot y = 0
∴ From equation (i), at x = 1 and cot y = 0, we get

 
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Let y be an implicit function of x defined by x2x – 2xx cot y – 1= 0. Then y(1) equalsa)1b)log 2c)–log 2d)–1Correct answer is option 'D'. Can you explain this answer?
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