The numerator of rational number is 2 less than the denominator when 1...
Supposed that denominator = x ,
so numerator = x -2 ,
when 1 is subtracted from both - ,
x-1 and x-2-1=x-3 ,,
rational number = (x-3)/(x-1)
The numerator of rational number is 2 less than the denominator when 1...
Understanding the Problem:
The problem states that the numerator of a rational number is 2 less than the denominator. When 1 is subtracted from both the numerator and denominator, the number remains the same. We need to find this rational number.
Solution:
Let's denote the numerator as 'n' and the denominator as 'd'.
Given: n = d - 2
When 1 is subtracted from both the numerator and denominator, the new rational number is (n-1)/(d-1).
According to the problem, this new rational number is equal to the original rational number, which can be represented as: n/d = (n-1)/(d-1)
Now, substitute the value of n from the first equation into the second equation:
d - 2 / d = (d - 2 - 1) / (d - 1)
Simplify the above equation:
d - 2 / d = (d - 3) / (d - 1)
Cross multiply to solve for 'd':
d(d - 3) = (d - 2)(d - 1)
d^2 - 3d = d^2 - 3d + 2
-3d = 2
d = -2/3
Therefore, the rational number is -2/3.
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