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a, b, c are integers, not all simultaneously equal and  ω is cube root of unity (ω ≠ 1), then minimum value of |a + bω + cω2| is (2005S)
  • a)
    0
  • b)
    1
  • c)
  • d)
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
a, b, c are integers, not all simultaneously equal and ω is cube...
Given that a, b, c are integers not all equal, w is cube root of unity ≠ 1,  then
| a + bω +cω2|
∴ The min value is obtained when any two are zero and third is a minimum magnitude integer i.e. 1.
Thus b = c = 0, a = 1 gives us the minimum value 1
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a, b, c are integers, not all simultaneously equal and ω is cube root of unity (ω ≠ 1), then minimum value of |a + bω + cω2| is (2005S)a)0b)1c)d)Correct answer is option 'B'. Can you explain this answer?
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