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a, b, c are integers, not all simultaneously equal and ω is cube root of unity (ω ≠ 1), then minimum value of |a + bω + cω2| is (2005S)a)0b)1c)d)Correct answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared
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the JEE exam syllabus. Information about a, b, c are integers, not all simultaneously equal and ω is cube root of unity (ω ≠ 1), then minimum value of |a + bω + cω2| is (2005S)a)0b)1c)d)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam.
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a, b, c are integers, not all simultaneously equal and ω is cube root of unity (ω ≠ 1), then minimum value of |a + bω + cω2| is (2005S)a)0b)1c)d)Correct answer is option 'B'. Can you explain this answer?, a detailed solution for a, b, c are integers, not all simultaneously equal and ω is cube root of unity (ω ≠ 1), then minimum value of |a + bω + cω2| is (2005S)a)0b)1c)d)Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of a, b, c are integers, not all simultaneously equal and ω is cube root of unity (ω ≠ 1), then minimum value of |a + bω + cω2| is (2005S)a)0b)1c)d)Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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