JEE Exam  >  JEE Questions  >  The gravitational field due to a mass distrib... Start Learning for Free
The gravitational field due to a mass distribution is I=k/x^3 in the direction (k is const).Taking the gravitational potential to be zero at infinity,its value at a distance x/√2 is?
Most Upvoted Answer
The gravitational field due to a mass distribution is I=k/x^3 in the d...
Community Answer
The gravitational field due to a mass distribution is I=k/x^3 in the d...
**Solution:**

Gravitational field due to a mass distribution is given by:
I=k/x^3 in the direction (k is const)

Let us consider a point mass 'M' at the origin.
Then, the gravitational potential due to this mass at a distance 'r' is given by:
V = -GM/r

We need to find the gravitational potential at a distance x/√2 from the origin.

**Step 1: Finding the gravitational field due to the point mass**

Let us find the gravitational field due to the point mass 'M' at a distance 'x' from the origin.
We know that the gravitational field due to a point mass is given by:
E = GM/x^2

Now, we can find the value of 'k' in terms of 'G' and 'M'.
We know that the gravitational field at a distance 'x' is given by:
I = k/x^3
Therefore, k = Ix^3

Substituting the value of 'k' in terms of 'I' and 'x' in the expression for gravitational field due to a point mass, we get:
E = GMI/x^5

**Step 2: Finding the gravitational potential due to the mass distribution**

We can use the concept of superposition to find the gravitational potential due to the mass distribution.
Let us divide the mass distribution into small point masses of mass 'dm'.
Then, the gravitational potential due to each point mass at a distance 'x' is given by:
dV = -Gdm/x

The total gravitational potential due to the mass distribution is given by:
V = ∫ dV

Integrating both sides with respect to 'dm', we get:
V = -G ∫ (dm/x)

Now, we need to express 'dm' in terms of the mass distribution.
We know that the mass of the mass distribution is given by:
M = ∫ dm

Therefore, dm = M(dx/L)^3, where 'L' is the total length of the mass distribution.
Substituting the value of 'dm' in the expression for gravitational potential, we get:
V = -GM ∫ (dx/x^3)

Integrating both sides, we get:
V = GM/x

Therefore, the gravitational potential due to the mass distribution is given by:
V = GM/x

**Step 3: Finding the gravitational potential at a distance x/√2**

We need to find the gravitational potential at a distance x/√2 from the origin.
Therefore, we need to substitute 'r' with 'x/√2' in the expression for gravitational potential due to a point mass.
We get:
V = -GM/(x/√2)

Simplifying, we get:
V = -√2 GM/x

Therefore, the gravitational potential at a distance x/√2 from the origin is -√2 GM/x.
Explore Courses for JEE exam
The gravitational field due to a mass distribution is I=k/x^3 in the direction (k is const).Taking the gravitational potential to be zero at infinity,its value at a distance x/√2 is?
Question Description
The gravitational field due to a mass distribution is I=k/x^3 in the direction (k is const).Taking the gravitational potential to be zero at infinity,its value at a distance x/√2 is? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The gravitational field due to a mass distribution is I=k/x^3 in the direction (k is const).Taking the gravitational potential to be zero at infinity,its value at a distance x/√2 is? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The gravitational field due to a mass distribution is I=k/x^3 in the direction (k is const).Taking the gravitational potential to be zero at infinity,its value at a distance x/√2 is?.
Solutions for The gravitational field due to a mass distribution is I=k/x^3 in the direction (k is const).Taking the gravitational potential to be zero at infinity,its value at a distance x/√2 is? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of The gravitational field due to a mass distribution is I=k/x^3 in the direction (k is const).Taking the gravitational potential to be zero at infinity,its value at a distance x/√2 is? defined & explained in the simplest way possible. Besides giving the explanation of The gravitational field due to a mass distribution is I=k/x^3 in the direction (k is const).Taking the gravitational potential to be zero at infinity,its value at a distance x/√2 is?, a detailed solution for The gravitational field due to a mass distribution is I=k/x^3 in the direction (k is const).Taking the gravitational potential to be zero at infinity,its value at a distance x/√2 is? has been provided alongside types of The gravitational field due to a mass distribution is I=k/x^3 in the direction (k is const).Taking the gravitational potential to be zero at infinity,its value at a distance x/√2 is? theory, EduRev gives you an ample number of questions to practice The gravitational field due to a mass distribution is I=k/x^3 in the direction (k is const).Taking the gravitational potential to be zero at infinity,its value at a distance x/√2 is? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev