Two insulating materials of thermal conductivity K and 2K are availabl...
Explanation:
When we need to lag a pipe carrying a hot fluid, we use insulating materials to reduce the heat loss from the pipe. Two insulating materials of thermal conductivity K and 2K are available for lagging a pipe carrying a hot fluid. If the radial thickness of each material is the same, then the following options are available:
a) Material with higher thermal conductivity should be used for the inner layer and one with lower thermal conductivity for the outer.
b) Material with lower thermal conductivity should be used for the inner layer and one with higher thermal conductivity for the outer.
c) It is immaterial in which sequence the insulating materials are used.
d) It is not possible to judge unless numerical values of dimensions are given.
Option 'B' is correct, and here is the explanation:
- Heat Flow: The heat flows from hot to cold, and the rate of heat flow is directly proportional to the temperature difference and inversely proportional to the thermal resistance.
- Thermal Conductivity: The thermal conductivity is the measure of a material's ability to conduct heat. A material with a higher thermal conductivity will conduct more heat, and a material with a lower thermal conductivity will conduct less heat.
- Radial Thickness: The radial thickness of the insulating materials is the same. It means that the heat flow will encounter the same thickness of both materials.
- Inner and Outer Layer: The question asks about the sequence of the insulating materials. It means that we have two layers of insulating materials. One will be the inner layer, and the other will be the outer layer.
Now, let's consider option 'A':
- Material with higher thermal conductivity should be used for the inner layer and one with lower thermal conductivity for the outer.
If we follow this option, then the material with higher thermal conductivity will be in contact with the hot pipe. It means that this material will conduct more heat from the pipe to the outer layer. The outer layer is of lower thermal conductivity, which means that it will conduct less heat away from the inner layer. Therefore, the heat flow will be high in the inner layer and low in the outer layer. As a result, the temperature difference between the inner and outer layers will be high, and the rate of heat flow will be high. It means that this option will not reduce the heat loss from the pipe.
Now, let's consider option 'B':
- Material with lower thermal conductivity should be used for the inner layer and one with higher thermal conductivity for the outer.
If we follow this option, then the material with lower thermal conductivity will be in contact with the hot pipe. It means that this material will conduct less heat from the pipe to the outer layer. The outer layer is of higher thermal conductivity, which means that it will conduct more heat away from the inner layer. Therefore, the heat flow will be low in the inner layer and high in the outer layer. As a result, the temperature difference between the inner and outer layers will be low, and the rate of heat flow will be low. It means that this option will reduce the heat loss from the pipe.
Therefore, option 'B' is the correct option.
Two insulating materials of thermal conductivity K and 2K are availabl...
To have lesser heat transfer rate b/w pipe(wire) and surrounding,always keep better insulated body i.e body having less K(thermal conductivity),should be keep next to metal body and having more k should be kept after that...so that Rth of conduction be higher
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