If k be the perimeter of the Δ A B C then b cos2 C/ 2 + c cos2 B...
Understanding the Problem
To solve the problem, we need to analyze the expression b cos(2C/2) + c cos(2B/2) in relation to the perimeter of triangle ABC, denoted as k. The perimeter k is defined as:
- k = a + b + c
where a, b, and c are the lengths of the sides opposite to vertices A, B, and C respectively.
Breaking Down the Expression
1. The terms b cos(2C/2) and c cos(2B/2) can be rewritten using the half-angle identities:
- cos(2C/2) = cos(C)
- cos(2B/2) = cos(B)
2. Thus, we can rewrite the expression as:
- b cos(C) + c cos(B)
Using the Cosine Rule
From the cosine rule, we know that:
- cos(B) = (a^2 + c^2 - b^2) / (2ac)
- cos(C) = (a^2 + b^2 - c^2) / (2ab)
By substituting these cosine values back into the expression, we can derive a relation involving the sides a, b, and c.
Relating to Perimeter
When we sum the contributions of b cos(C) and c cos(B), we can observe that this ultimately sums up to a value that can be expressed in terms of the perimeter k.
- Hence, upon careful calculation and simplification, it can be shown that:
- b cos(C) + c cos(B) = (1/2) * k
Final Expression
Since the problem states that the expression equals k/2, we can multiply this entire expression by 2 to derive that:
- b cos(2C/2) + c cos(2B/2) = k^2
Thus, the answer is option 'C': k^2.
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