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A 25 kV A single-phase motor has a power factor of 0.8 lag. A 10 kV A capacitor is connected for powerfactor correction. Calculate the input apparent power in kV A taken from the mains and its power factor when the motor is (a) on half load; (b) on full load.?
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A 25 kV A single-phase motor has a power factor of 0.8 lag. A 10 kV A ...
(a) On half load, the input apparent power in kV A taken from the mains is 25 kV A and the power factor when the motor is on half load is 0.8 lag.
(b) On full load, the input apparent power in kV A taken from the mains is 35 kV A and the power factor when the motor is on full load is 0.88 lag.
(b) On full load, the input apparent power in kV A taken from the mains is 35 kV A and the power factor when the motor is on full load is 0.88 lag.
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A 25 kV A single-phase motor has a power factor of 0.8 lag. A 10 kV A ...
Given:
- Voltage (V) = 25 kV
- Power factor (PF) = 0.8 lagging
- Capacitor voltage (Vc) = 10 kV
To find:
- Input apparent power (S) in kVA
- Power factor when the motor is on half load and full load
The input apparent power (S) is given by the formula:
S = V * I
However, since the power factor is given, we can use the formula:
S = P / PF
Where P is the active power (in this case, the power consumed by the motor).
To find the active power, we can use the formula:
P = V * I * PF
On half load:
Assuming the motor is running at half load, the active power can be calculated as follows:
P = V * I * PF
P = 25 kV * I * 0.8
P = 20 kV * I
On full load:
Assuming the motor is running at full load, the active power remains the same as on half load.
Therefore, the input apparent power (S) can be calculated as follows:
S = P / PF
S = (20 kV * I) / 0.8
S = 25 kV * I
The power factor (PF) can be calculated using the formula:
PF = cos(θ)
Where θ is the angle between the voltage (V) and current (I) waveforms.
On half load:
The power factor is given as 0.8 lagging, which means the angle θ is positive.
On full load:
The power factor remains the same as on half load.
Therefore, the power factor is 0.8 lagging for both half load and full load.
Note:
Since the capacitor is connected for power factor correction, it is assumed that the power factor is improved to a value close to unity (1) by the capacitor. However, the exact power factor value cannot be determined without knowing the capacitance of the capacitor and the motor's reactive power.
- Voltage (V) = 25 kV
- Power factor (PF) = 0.8 lagging
- Capacitor voltage (Vc) = 10 kV
To find:
- Input apparent power (S) in kVA
- Power factor when the motor is on half load and full load
1. Calculating Input Apparent Power (S)
The input apparent power (S) is given by the formula:
S = V * I
However, since the power factor is given, we can use the formula:
S = P / PF
Where P is the active power (in this case, the power consumed by the motor).
To find the active power, we can use the formula:
P = V * I * PF
On half load:
Assuming the motor is running at half load, the active power can be calculated as follows:
P = V * I * PF
P = 25 kV * I * 0.8
P = 20 kV * I
On full load:
Assuming the motor is running at full load, the active power remains the same as on half load.
Therefore, the input apparent power (S) can be calculated as follows:
S = P / PF
S = (20 kV * I) / 0.8
S = 25 kV * I
2. Calculating Power Factor
The power factor (PF) can be calculated using the formula:
PF = cos(θ)
Where θ is the angle between the voltage (V) and current (I) waveforms.
On half load:
The power factor is given as 0.8 lagging, which means the angle θ is positive.
On full load:
The power factor remains the same as on half load.
Therefore, the power factor is 0.8 lagging for both half load and full load.
Note:
Since the capacitor is connected for power factor correction, it is assumed that the power factor is improved to a value close to unity (1) by the capacitor. However, the exact power factor value cannot be determined without knowing the capacitance of the capacitor and the motor's reactive power.
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A 25 kV A single-phase motor has a power factor of 0.8 lag. A 10 kV A capacitor is connected for powerfactor correction. Calculate the input apparent power in kV A taken from the mains and its power factor when the motor is (a) on half load; (b) on full load.?
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A 25 kV A single-phase motor has a power factor of 0.8 lag. A 10 kV A capacitor is connected for powerfactor correction. Calculate the input apparent power in kV A taken from the mains and its power factor when the motor is (a) on half load; (b) on full load.? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A 25 kV A single-phase motor has a power factor of 0.8 lag. A 10 kV A capacitor is connected for powerfactor correction. Calculate the input apparent power in kV A taken from the mains and its power factor when the motor is (a) on half load; (b) on full load.? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 25 kV A single-phase motor has a power factor of 0.8 lag. A 10 kV A capacitor is connected for powerfactor correction. Calculate the input apparent power in kV A taken from the mains and its power factor when the motor is (a) on half load; (b) on full load.?.
A 25 kV A single-phase motor has a power factor of 0.8 lag. A 10 kV A capacitor is connected for powerfactor correction. Calculate the input apparent power in kV A taken from the mains and its power factor when the motor is (a) on half load; (b) on full load.? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A 25 kV A single-phase motor has a power factor of 0.8 lag. A 10 kV A capacitor is connected for powerfactor correction. Calculate the input apparent power in kV A taken from the mains and its power factor when the motor is (a) on half load; (b) on full load.? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 25 kV A single-phase motor has a power factor of 0.8 lag. A 10 kV A capacitor is connected for powerfactor correction. Calculate the input apparent power in kV A taken from the mains and its power factor when the motor is (a) on half load; (b) on full load.?.
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A 25 kV A single-phase motor has a power factor of 0.8 lag. A 10 kV A capacitor is connected for powerfactor correction. Calculate the input apparent power in kV A taken from the mains and its power factor when the motor is (a) on half load; (b) on full load.?, a detailed solution for A 25 kV A single-phase motor has a power factor of 0.8 lag. A 10 kV A capacitor is connected for powerfactor correction. Calculate the input apparent power in kV A taken from the mains and its power factor when the motor is (a) on half load; (b) on full load.? has been provided alongside types of A 25 kV A single-phase motor has a power factor of 0.8 lag. A 10 kV A capacitor is connected for powerfactor correction. Calculate the input apparent power in kV A taken from the mains and its power factor when the motor is (a) on half load; (b) on full load.? theory, EduRev gives you an
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