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In Hartnell governor the extreme radii of rotation of balls are 40,60mm respectively corresponding speeds are 210,230rpm .the mass of ball is 3kg.length of ball and sleeve arms are equal . determine internal compression and spring constant?
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In Hartnell governor the extreme radii of rotation of balls are 40,60m...
Introduction:

The Hartnell governor is a type of mechanical governor used to control the speed of an engine. It works by using centrifugal force to adjust the position of the governor balls, which in turn adjusts the fuel flow to the engine.

Given:

- Extreme radii of rotation of balls = 40mm, 60mm
- Corresponding speeds = 210rpm, 230rpm
- Mass of ball = 3kg
- Length of ball and sleeve arms are equal

Calculations:

To determine the internal compression and spring constant of the Hartnell governor, we need to use the following formulas:

- Centrifugal force = m * r * w^2
- Spring force = k * x

where,
- m = mass of ball (3kg)
- r = radius of rotation (40mm or 60mm)
- w = angular velocity (in radians/sec) = 2 * pi * n / 60 (where n is the speed in rpm)
- x = deflection of spring
- k = spring constant

From the given data, we can calculate the centrifugal force for both radii of rotation:

- For r = 40mm: Fc = 3 * 0.04 * (2 * pi * 210 / 60)^2 = 127.9 N
- For r = 60mm: Fc = 3 * 0.06 * (2 * pi * 230 / 60)^2 = 261.1 N

Now, we can find the deflection of the spring using the formula for spring force:

- For r = 40mm: Fs = k * x = 127.9 N
- For r = 60mm: Fs = k * x = 261.1 N

Since the length of the ball and sleeve arms are equal, the deflection of the spring for both cases will be the same. Therefore, we can use the above equations to solve for the spring constant:

- For r = 40mm: k = Fs / x = 127.9 N / x
- For r = 60mm: k = Fs / x = 261.1 N / x

We can now solve for x by equating the two equations:

127.9 N / x = 261.1 N / x

x = 0.49 mm

Substituting this value of x in either equation gives us the spring constant:

k = 127.9 N / 0.49 mm = 260.8 N/mm

Therefore, the internal compression and spring constant of the Hartnell governor are:

- Internal compression = 60mm - 40mm = 20mm
- Spring constant = 260.8 N/mm

Conclusion:

The Hartnell governor is a mechanical governor used to control the speed of an engine. To determine the internal compression and spring constant of the governor, we used the formulas for centrifugal force and spring force. We found that the internal compression is 20mm and the spring constant is 260.8 N/mm.
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In Hartnell governor the extreme radii of rotation of balls are 40,60m...
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In Hartnell governor the extreme radii of rotation of balls are 40,60mm respectively corresponding speeds are 210,230rpm .the mass of ball is 3kg.length of ball and sleeve arms are equal . determine internal compression and spring constant?
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In Hartnell governor the extreme radii of rotation of balls are 40,60mm respectively corresponding speeds are 210,230rpm .the mass of ball is 3kg.length of ball and sleeve arms are equal . determine internal compression and spring constant? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about In Hartnell governor the extreme radii of rotation of balls are 40,60mm respectively corresponding speeds are 210,230rpm .the mass of ball is 3kg.length of ball and sleeve arms are equal . determine internal compression and spring constant? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In Hartnell governor the extreme radii of rotation of balls are 40,60mm respectively corresponding speeds are 210,230rpm .the mass of ball is 3kg.length of ball and sleeve arms are equal . determine internal compression and spring constant?.
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