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The propagation of radio waves with frequency 2 MHz to 30 MHZ is due to A. space wave B. options wave C. Ground wave D. Sky wave ANSWER Ans: (D Please explain?
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The propagation of radio waves with frequency 2 MHz to 30 MHZ is due t...
Sky wave is the wave which return from ionosphere after transmission i.e. it is not penetrated.
The sky wave propagation is suitable for radio waves of frequency 2 MHz to 30 MHz.
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The propagation of radio waves with frequency 2 MHz to 30 MHZ is due t...
The propagation of radio waves with frequencies ranging from 2 MHz to 30 MHz is mainly due to the sky wave propagation.

Sky Wave Propagation:
Sky wave propagation occurs when radio waves are reflected by the ionosphere back to the Earth's surface. The ionosphere is a layer of the Earth's upper atmosphere that contains a high concentration of ions and free electrons. When radio waves encounter this ionized layer, they can be refracted or reflected back to the Earth.

Key Points:
- Frequency Range: The frequency range of 2 MHz to 30 MHz corresponds to the High Frequency (HF) band. This range of frequencies is ideal for sky wave propagation.
- Ionospheric Reflection: The radio waves in this frequency range interact with the ionosphere, specifically the F-layer and E-layer, causing them to bend or reflect back towards the Earth's surface.
- Multiple Hops: Sky wave propagation enables radio signals to travel over long distances by undergoing multiple hops between the Earth's surface and the ionosphere. This allows for communication beyond the line of sight.
- Day and Night Variations: The efficiency of sky wave propagation is influenced by various factors, including the time of day. During the day, the D-layer of the ionosphere absorbs the lower frequency radio waves, limiting the effectiveness of sky wave propagation. However, at night, the D-layer disappears, allowing the lower frequency radio waves to penetrate the ionosphere and reach longer distances.
- Angle of Incidence: The angle at which the radio waves hit the ionosphere determines whether they are refracted or reflected. The optimal angle for sky wave propagation is usually between 5 and 30 degrees.

Conclusion:
In conclusion, the propagation of radio waves with frequencies ranging from 2 MHz to 30 MHz is primarily due to sky wave propagation. The interaction of these radio waves with the ionosphere allows them to be refracted or reflected back to the Earth's surface, enabling long-distance communication. Understanding the principles of sky wave propagation is essential for designing and operating HF radio communication systems.
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Read the following text and answer the following questions on the basis of the same:Diffraction in a hall:A and B went to purchase a ticket of a music programme. But unfortunately only one ticket was left. They purchased the single ticket and decided that A would be in the hall during the 1st half and B during the 2nd half.Both of them reached the hall together. A entered the hall and found that the seat was behind a pillar which creates an obstacle. He was disappointed. He thought that he would not be able to hear the programme properly.B was waiting outside the closed door. The door was not fully closed. There was a little opening.But surprisingly, A could hear the music programme.This happened due to diffraction of sound.The fact we hear sounds around corners and around barriers involves both diffraction and reflection of sound.Diffraction in such cases helps the sound to "bend around" the obstacles.In fact, diffraction is more pronounced with longer wavelengths implies that we can hear low frequencies around obstacles better than high frequencies.B was outside the door. He could also hear the programme. But he noticed that when the door opening is comparatively less he could hear the programme even being little away from the door. This is because when the width of the opening is larger than the wavelength of the wave passing through the gap then it does not spread out much on the other side. But when the opening is smaller than the wavelength more diffraction occurs and the waves spread out greatly – with semicircular wavefront. The opening in this case functions as a localized source of sound.Q. The minimum and maximum frequencies in the musical programme were 550 Hz and 10 kHz. Which frequency was better audible around the pillar obstacle?

The propagation of radio waves with frequency 2 MHz to 30 MHZ is due to A. space wave B. options wave C. Ground wave D. Sky wave ANSWER Ans: (D Please explain?
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