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An element crystallises in fcc lattice having edge length 40 0 pm. Maximum radius of the atom which can be placed in the interstitial site without distorting the structure is
  • a)
    58.55pm
  • b)
    117pm
  • c)
    166pm
  • d)
    83pm
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
An element crystallises in fcc lattice having edge length 40 0 pm. Max...
 (a) For fcc structure
 = 0.414 for octahedral void
= 0.225 for tetrahedral void 
Thus, maximum packing can be for octahedral void
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An element crystallises in fcc lattice having edge length 40 0 pm. Maximum radius of the atom which can be placed in the interstitial site without distorting the structure isa)58.55pmb)117pmc)166pmd)83pmCorrect answer is option 'A'. Can you explain this answer?
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An element crystallises in fcc lattice having edge length 40 0 pm. Maximum radius of the atom which can be placed in the interstitial site without distorting the structure isa)58.55pmb)117pmc)166pmd)83pmCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An element crystallises in fcc lattice having edge length 40 0 pm. Maximum radius of the atom which can be placed in the interstitial site without distorting the structure isa)58.55pmb)117pmc)166pmd)83pmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An element crystallises in fcc lattice having edge length 40 0 pm. Maximum radius of the atom which can be placed in the interstitial site without distorting the structure isa)58.55pmb)117pmc)166pmd)83pmCorrect answer is option 'A'. Can you explain this answer?.
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