ABCDEF is a regular polygon. Two poles at C and D are standing vertica...
Suppose the side of the hexagon is ‘a’ unit;
First we need to find out the values of AC and AD;
In triangle ABC, applying the sine rule;
⇒ Sin120/AC = Sin30/BC
⇒ √3/2AC = 1/2a
⇒ AC = a√3 unitIn triangle ACD;
∠ACD = 120 – 30 = 90°
Hence triangle ACD is a right angle triangle;
∴ Sin30 = CD/AD
⇒ ½ = a/AD
⇒ AD = 2a unitNow in the figure we can see that, CP and DQ are the poles at point C and D and they are subtending 30° and 60° at A respectively;
In triangle ACP;
⇒ Tan30 = PC/AC
⇒ 1/√3 = PC/a√3
⇒ PC = a unit
In triangle ADQ;
⇒ Tan60 = QD/AD
⇒ √3 = QD/2a
⇒ QD = 2a√3 unit
∴ Ratio of the height of the pole at C to that of the pole at D = PC : QD = 1 : 2√3
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ABCDEF is a regular polygon. Two poles at C and D are standing vertica...
We can conclude that C and D are the vertices of the regular polygon ABCDEF. Since ABCDEF is a regular polygon, all sides and angles are equal.
Let's call the side length of the polygon as s.
Since C and D are vertically standing poles, the angle of elevation from both A and B would be 90 degrees.
Also, since ABCDEF is a regular polygon, the sum of the interior angles is given by (n-2) * 180 degrees, where n is the number of sides of the polygon.
Since ABCDEF is a regular polygon, the sum of the interior angles is also equal to 360 degrees.
Therefore, (n-2) * 180 = 360.
Simplifying the equation, we get (n-2) = 2.
Solving for n, we get n = 4.
So, ABCDEF is a regular polygon with 4 sides, which is a square.
Therefore, the angle of elevation from C and D to any vertex of the square ABCDEF is 30 degrees.