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An equimolar mixture of toluene and chlorobenzene is treated with a mixture of conc. H2SO4 and conc. HNO3.Indicate the correct statement from the following
  • a)
     p-nitrotoluene is formed in excess
  • b)
    equimolar amounts of p-nitrotoluene and p-nitrochlorobenzene are formed
  • c)
     p-nitrochlorobenzene is formed in excess
  • d)
    m-nitrochlorobenzene is formed in excess
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
An equimolar mixture of toluene and chlorobenzene is treated with a mi...
 – CH3 is activating group due to +I effect and hyperconjugation.
But for – Cl, – I > + R effect.
∴CH3 is weakly activating and – Cl is weakly deactivating
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Most Upvoted Answer
An equimolar mixture of toluene and chlorobenzene is treated with a mi...
Explanation:

When an equimolar mixture of toluene and chlorobenzene is treated with a mixture of concentrated sulfuric acid (H2SO4) and concentrated nitric acid (HNO3), the following reactions occur:

1) Nitration of Toluene:
Toluene reacts with the mixture of concentrated H2SO4 and HNO3 to form p-nitrotoluene. This reaction is known as nitration. The reaction occurs through an electrophilic aromatic substitution mechanism. The nitronium ion (NO2+) is generated as an electrophile in the presence of the acid mixture, which attacks the aromatic ring of toluene to give p-nitrotoluene as the major product.

2) Nitration of Chlorobenzene:
Chlorobenzene also reacts with the mixture of concentrated H2SO4 and HNO3 to form p-nitrochlorobenzene. Similar to the nitration of toluene, the nitronium ion (NO2+) is generated as an electrophile and attacks the aromatic ring of chlorobenzene to give p-nitrochlorobenzene as the major product.

Reason for Correct Answer:
Since an equimolar mixture of toluene and chlorobenzene is used, the concentration of both compounds is the same. Therefore, the reactivity of both compounds towards nitration is expected to be similar. As a result, equal amounts of p-nitrotoluene and p-nitrochlorobenzene will be formed. However, the statement "p-nitrotoluene is formed in excess" is incorrect because it implies that p-nitrotoluene is the major product, which is not the case. Hence, option A is the correct answer.
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An equimolar mixture of toluene and chlorobenzene is treated with a mixture of conc. H2SO4 and conc. HNO3.Indicate the correct statement from the followinga)p-nitrotoluene is formed in excessb)equimolar amounts of p-nitrotoluene and p-nitrochlorobenzene are formedc)p-nitrochlorobenzene is formed in excessd)m-nitrochlorobenzene is formed in excessCorrect answer is option 'A'. Can you explain this answer?
Question Description
An equimolar mixture of toluene and chlorobenzene is treated with a mixture of conc. H2SO4 and conc. HNO3.Indicate the correct statement from the followinga)p-nitrotoluene is formed in excessb)equimolar amounts of p-nitrotoluene and p-nitrochlorobenzene are formedc)p-nitrochlorobenzene is formed in excessd)m-nitrochlorobenzene is formed in excessCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An equimolar mixture of toluene and chlorobenzene is treated with a mixture of conc. H2SO4 and conc. HNO3.Indicate the correct statement from the followinga)p-nitrotoluene is formed in excessb)equimolar amounts of p-nitrotoluene and p-nitrochlorobenzene are formedc)p-nitrochlorobenzene is formed in excessd)m-nitrochlorobenzene is formed in excessCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An equimolar mixture of toluene and chlorobenzene is treated with a mixture of conc. H2SO4 and conc. HNO3.Indicate the correct statement from the followinga)p-nitrotoluene is formed in excessb)equimolar amounts of p-nitrotoluene and p-nitrochlorobenzene are formedc)p-nitrochlorobenzene is formed in excessd)m-nitrochlorobenzene is formed in excessCorrect answer is option 'A'. Can you explain this answer?.
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