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From the top of a building 90 m high, the angles of depression of the top and bottom of a tree are 30° and 45° respectively. What is the height of the tree?
  • a)
    30√3 m
  • b)
    90 - 30√3 m
  • c)
    90 + 30√3 m
  • d)
    60 + 30√3 m
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
From the top of a building 90 m high, the angles of depression of the ...

Let the height of the tree = h m;
In the figure;
From triangle ADB;
tan45 = AB/DB
⇒ 1 = 90/DB
⇒ DB = 90 m
∴ CE = DB = 90 m
From triangle CAE;
tan30 = AE/CE
⇒ 1/√3 = AE/90
⇒ AE = 90/√3 = 30√3 m
∴ h = 90 - AE = (90 - 30√3) m
∴ Height of the tree = (90 - 30√3) m
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Most Upvoted Answer
From the top of a building 90 m high, the angles of depression of the ...
We can use trigonometry to solve this problem.

Let's say the distance from the top of the building to the tree is x.

From the top of the building, the angle of depression to the top of the tree is 30°. This means that the opposite side of the triangle is x and the adjacent side is 90 m.

Using the tangent function, we can write:

tan(30°) = opposite/adjacent
tan(30°) = x/90

Simplifying this equation, we get:

x = 90 * tan(30°)
x = 90 * 0.5774
x ≈ 52.0 m

So, the distance from the top of the building to the tree is approximately 52.0 m.
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From the top of a building 90 m high, the angles of depression of the top and bottom of a tree are 30° and 45° respectively. What is the height of the tree?a)30√3 mb)90 - 30√3 mc)90 + 30√3 md)60 + 30√3 mCorrect answer is option 'B'. Can you explain this answer?
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