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When a certain metal surface is illuminated with light of frequency ν , the stopping potential for photoelectric current is νo When the same surface is illuminated by light of frequency  v/2 the stopping potential is v0/4 The threshold frequency for photoelectric emission is
  • a)
    v/6
  • b)
    v/3
  • c)
    2v/3
  • d)
    4v/3
Correct answer is option 'B'. Can you explain this answer?
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When a certain metal surface is illuminated with light of frequency&nu...
solving equation (1) and (2) ,v/3
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When a certain metal surface is illuminated with light of frequency&nu...
When a certain metal surface is illuminated with light of frequency, the electrons in the metal surface can absorb the energy from the light and get excited to higher energy levels. This phenomenon is known as the photoelectric effect.

The frequency of the light is directly proportional to the energy of the photons. If the frequency of the light is below a certain threshold frequency, no electrons will be emitted from the metal surface regardless of the intensity of the light. However, if the frequency of the light exceeds the threshold frequency, electrons will be emitted from the metal surface.

The energy of the emitted electrons is dependent on the frequency of the light. Higher frequency light corresponds to higher energy electrons. This relationship is described by the equation E = hf, where E is the energy of the photon, h is Planck's constant, and f is the frequency of the light.

In summary, when a certain metal surface is illuminated with light of frequency, the electrons in the metal surface can absorb the energy from the light and get excited to higher energy levels, leading to the emission of electrons from the surface. The energy of the emitted electrons is determined by the frequency of the light.
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When a certain metal surface is illuminated with light of frequencyν , the stopping potential for photoelectric current isνoWhen the same surface is illuminated by light of frequency v/2the stopping potential is v0/4The threshold frequency for photoelectric emission isa)v/6b)v/3c)2v/3d)4v/3Correct answer is option 'B'. Can you explain this answer?
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