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A Wheatstone bridge has the resistances 10 Ω , 10 Ω , 10Ω and 30 Ω in its four arms. What resistance joined in parallel to the 30 resistance will bring it to the balanced condition?
  • a)
  • b)
  • c)
    10Ω
  • d)
    15Ω
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A Wheatstone bridge has the resistances 10Ω , 10Ω , 10&Ome...
 for a balanced bridge. R = 10 Ω
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A Wheatstone bridge has the resistances 10Ω , 10Ω , 10&Ome...
Ω, 20 Ω, 30 Ω and 40 Ω. If a voltage of 12 V is applied across the bridge, what is the voltage drop across the 30 Ω resistor?

To solve this problem, we need to use the formula for the voltage drop across a resistor in a Wheatstone bridge:

V = (R2 / (R1 + R2)) * Vin - (R4 / (R3 + R4)) * Vin

where V is the voltage drop across the resistor we are interested in, R1, R2, R3 and R4 are the resistances in the Wheatstone bridge, Vin is the voltage applied across the bridge.

Plugging in the values we have:

V = (20 / (10 + 20)) * 12 - (40 / (30 + 40)) * 12

V = 0.4 * 12 - 0.57 * 12

V = 4.8 - 6.84

V = -2.04 V

Therefore, the voltage drop across the 30 Ω resistor is -2.04 V. Note that the negative sign indicates that the voltage drop is in the opposite direction of the current flow.
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A Wheatstone bridge has the resistances 10Ω , 10Ω , 10Ω and 30 Ω in its four arms. What resistance joined in parallel to the 30 resistance will bring it to the balanced condition?a)2Ωb)5Ωc)10Ωd)15ΩCorrect answer is option 'D'. Can you explain this answer?
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