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A box of mass 2 kg is placed on the roof of a car. The box would remain stationary until the car attains a maximum acceleration. Coefficient of static friction between the box and the roof of the car is 0.2 and g = 10 ms–2.This maximum acceleration of the car, for the box to remain stationary, is
  • a)
    8 ms–2
  • b)
    6 ms–2
  • c)
    4 ms–2
  • d)
    2 ms–2
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A box of mass 2 kg is placed on the roof of a car. The box would remai...
amax = μg =0.2x 10 = 2 m/s2
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A box of mass 2 kg is placed on the roof of a car. The box would remai...
Understanding the problem:
To determine the maximum acceleration of the car for the box to remain stationary on the roof, we need to consider the forces acting on the box.

Forces acting on the box:
- Weight of the box (mg)
- Normal force from the car roof (N)
- Static friction force (fs)

Equilibrium condition:
For the box to remain stationary, the static friction force must balance the component of the weight of the box along the roof of the car.

Calculating the maximum acceleration:
The maximum static friction force is given by fs = μsN, where μs is the coefficient of static friction and N is the normal force.
Considering the forces in the vertical direction:
mg = N
N = 2 kg * 10 m/s^2 = 20 N
Therefore, the maximum static friction force is fs = 0.2 * 20 = 4 N.
The maximum static friction force is also the force required to give the box an acceleration equal to the acceleration of the car.
Therefore, fs = ma
4 = 2a
a = 2 m/s^2
Therefore, the maximum acceleration of the car for the box to remain stationary is 2 m/s^2, which corresponds to option 'D'.
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A box of mass 2 kg is placed on the roof of a car. The box would remain stationary until the car attains a maximum acceleration. Coefficient of static friction between the box and the roof of the car is 0.2 and g = 10 ms–2.This maximum acceleration of the car, for the box to remain stationary, isa)8 ms–2b)6 ms–2c)4 ms–2d)2 ms–2Correct answer is option 'D'. Can you explain this answer?
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A box of mass 2 kg is placed on the roof of a car. The box would remain stationary until the car attains a maximum acceleration. Coefficient of static friction between the box and the roof of the car is 0.2 and g = 10 ms–2.This maximum acceleration of the car, for the box to remain stationary, isa)8 ms–2b)6 ms–2c)4 ms–2d)2 ms–2Correct answer is option 'D'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A box of mass 2 kg is placed on the roof of a car. The box would remain stationary until the car attains a maximum acceleration. Coefficient of static friction between the box and the roof of the car is 0.2 and g = 10 ms–2.This maximum acceleration of the car, for the box to remain stationary, isa)8 ms–2b)6 ms–2c)4 ms–2d)2 ms–2Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A box of mass 2 kg is placed on the roof of a car. The box would remain stationary until the car attains a maximum acceleration. Coefficient of static friction between the box and the roof of the car is 0.2 and g = 10 ms–2.This maximum acceleration of the car, for the box to remain stationary, isa)8 ms–2b)6 ms–2c)4 ms–2d)2 ms–2Correct answer is option 'D'. Can you explain this answer?.
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