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A car having a mass of 1000 kg is moving at a speed of 30 metres/sec. Brakes are applied to bring the car to rest. If the frictional force between the tyres and the road surface is 5000 newtons, the car will come to rest in
- a)5 seconds
- b)10 seconds
- c)12 seconds
- d)6 seconds
Correct answer is option 'D'. Can you explain this answer?
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A car having a mass of 1000 kg is moving at a speed of 30 metres/sec. ...
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A car having a mass of 1000 kg is moving at a speed of 30 metres/sec. ...
Solution:
Given:
Mass of the car (m) = 1000 kg
Initial velocity of the car (u) = 30 m/s
Frictional force (F) = 5000 N
We need to find the time taken by the car to come to rest.
Using Newton's second law of motion, we know that the net force acting on an object is equal to the product of its mass and acceleration.
F = ma
In this case, the net force acting on the car is the frictional force.
Frictional force (F) = ma
Rearranging the equation, we get:
a = F/m
Now, we can calculate the acceleration of the car using the given values:
a = 5000 N / 1000 kg
a = 5 m/s^2
The negative sign indicates that the acceleration is in the opposite direction to the motion of the car.
Using the first equation of motion, we know that the final velocity of the car (v) when it comes to rest is 0 m/s.
v = u + at
Substituting the values, we get:
0 = 30 m/s + (-5 m/s^2)t
Rearranging the equation, we get:
5t = 30
t = 30/5
t = 6 seconds
Therefore, the car will come to rest in 6 seconds. Hence, the correct answer is option D.
Given:
Mass of the car (m) = 1000 kg
Initial velocity of the car (u) = 30 m/s
Frictional force (F) = 5000 N
We need to find the time taken by the car to come to rest.
Using Newton's second law of motion, we know that the net force acting on an object is equal to the product of its mass and acceleration.
F = ma
In this case, the net force acting on the car is the frictional force.
Frictional force (F) = ma
Rearranging the equation, we get:
a = F/m
Now, we can calculate the acceleration of the car using the given values:
a = 5000 N / 1000 kg
a = 5 m/s^2
The negative sign indicates that the acceleration is in the opposite direction to the motion of the car.
Using the first equation of motion, we know that the final velocity of the car (v) when it comes to rest is 0 m/s.
v = u + at
Substituting the values, we get:
0 = 30 m/s + (-5 m/s^2)t
Rearranging the equation, we get:
5t = 30
t = 30/5
t = 6 seconds
Therefore, the car will come to rest in 6 seconds. Hence, the correct answer is option D.
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A car having a mass of 1000 kg is moving at a speed of 30 metres/sec. Brakes are applied to bring the car to rest. If the frictional force between the tyres and the road surface is 5000 newtons, the car will come to rest ina)5 secondsb)10 secondsc)12 secondsd)6 secondsCorrect answer is option 'D'. Can you explain this answer?
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A car having a mass of 1000 kg is moving at a speed of 30 metres/sec. Brakes are applied to bring the car to rest. If the frictional force between the tyres and the road surface is 5000 newtons, the car will come to rest ina)5 secondsb)10 secondsc)12 secondsd)6 secondsCorrect answer is option 'D'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A car having a mass of 1000 kg is moving at a speed of 30 metres/sec. Brakes are applied to bring the car to rest. If the frictional force between the tyres and the road surface is 5000 newtons, the car will come to rest ina)5 secondsb)10 secondsc)12 secondsd)6 secondsCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car having a mass of 1000 kg is moving at a speed of 30 metres/sec. Brakes are applied to bring the car to rest. If the frictional force between the tyres and the road surface is 5000 newtons, the car will come to rest ina)5 secondsb)10 secondsc)12 secondsd)6 secondsCorrect answer is option 'D'. Can you explain this answer?.
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