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If ω ≠ 1 is a cube root of unity, then the sum of the series S = 1 + 2ω + 3ω ² + .......... + 3nω 3n – 1 is
  • a)
    3n/(ω – 1)
  • b)
    3n(ω – 1)
  • c)
    (ω – 1)/3n
  • d)
    0
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
If ω ≠ 1 is a cube root of unity, then the sum of the series ...
S = 1 + 2ω + 3ω ² + .......... + 3nω 3n – 1
Sω = ω + ω ² + .......... + (3n-1)ω 3n – 1 + 3nωn
s(1 – ω) = 1 + ω + ω² + ...........+ ω3n–1 – 3nω3h
 = 0 – 3n
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If ω ≠ 1 is a cube root of unity, then the sum of the series S = 1 + 2ω + 3ω ² + .......... + 3nω 3n – 1 isa)3n/(ω – 1)b)3n(ω – 1)c)(ω – 1)/3nd)0Correct answer is option 'A'. Can you explain this answer?
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If ω ≠ 1 is a cube root of unity, then the sum of the series S = 1 + 2ω + 3ω ² + .......... + 3nω 3n – 1 isa)3n/(ω – 1)b)3n(ω – 1)c)(ω – 1)/3nd)0Correct answer is option 'A'. Can you explain this answer? for 2024 is part of preparation. The Question and answers have been prepared according to the exam syllabus. Information about If ω ≠ 1 is a cube root of unity, then the sum of the series S = 1 + 2ω + 3ω ² + .......... + 3nω 3n – 1 isa)3n/(ω – 1)b)3n(ω – 1)c)(ω – 1)/3nd)0Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If ω ≠ 1 is a cube root of unity, then the sum of the series S = 1 + 2ω + 3ω ² + .......... + 3nω 3n – 1 isa)3n/(ω – 1)b)3n(ω – 1)c)(ω – 1)/3nd)0Correct answer is option 'A'. Can you explain this answer?.
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