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A solution containing 250 ppm of CuSO4 · 5H2O (formula weight = 250) has an absorbance of 0.1 measured in 1 cm cell at 600 nm. Calculate the molar absorptivity (e) of CuSO4 · 5H2O in L M-1 cm-1 . When 25 mL of Na2EDTA (aq) solution is titrated against Na2EDTA (aq) solution, it consumes at 50 mL of Na2EDTA (aq) solution. Calculate the concentration of Na2EDTA (aq) solution in moles L-1 .
Correct answer is '= 102 litr mol-1 cm -1'. Can you explain this answer?
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Verified Answer
A solution containing 250 ppm of CuSO4 5H2O (formula weight = 250) ha...
C = 250 ppm = 10–3 mol ltr.
A = 0.1, x = 1 cm
A = 0.1, x = 1 cm
= 102 litr mol-1 cm -1
Most Upvoted Answer
A solution containing 250 ppm of CuSO4 5H2O (formula weight = 250) ha...
Calculation of Molar Absorptivity (e)
Given data:
- Concentration of CuSO4 5H2O solution = 250 ppm = 250 mg/L
- Absorbance (A) = 0.1
- Path length (l) = 1 cm
- Formula weight of CuSO4 5H2O = 250 g/mol
Step 1: Calculation of moles of CuSO4 5H2O
First, we need to calculate the moles of CuSO4 5H2O present in the solution using the given concentration and formula weight.
Moles of CuSO4 5H2O = (Concentration * Volume) / Formula weight
Concentration is given in mg/L, so we need to convert it to g/L:
Concentration = 250 mg/L = 0.25 g/L
Volume is not given, so we assume it to be 1 L (since concentration is given in mg/L).
Moles of CuSO4 5H2O = (0.25 g/L * 1 L) / 250 g/mol
Moles of CuSO4 5H2O = 0.001 mol
Step 2: Calculation of molar absorptivity (e)
The molar absorptivity (e) can be calculated using the Beer-Lambert Law equation:
A = e * c * l
Where:
A = Absorbance
e = Molar absorptivity
c = Concentration in mol/L
l = Path length in cm
Rearranging the equation, we can solve for e:
e = A / (c * l)
Substituting the given values:
e = 0.1 / (0.001 mol/L * 1 cm)
e = 100 L/mol/cm
Calculation of Concentration of Na2EDTA (aq) Solution
Given data:
- Volume of Na2EDTA (aq) solution used = 25 mL
- Volume of Na2EDTA (aq) solution consumed = 50 mL
Step 1: Calculation of moles of Na2EDTA
The moles of Na2EDTA can be calculated using the volume and concentration of Na2EDTA (aq) solution consumed.
Moles of Na2EDTA = Volume * Concentration
Since the volume and concentration are in mL, we need to convert them to L:
Volume = 50 mL = 0.05 L
Moles of Na2EDTA = 0.05 L * Concentration
Step 2: Calculation of concentration of Na2EDTA (aq) solution
Now we can calculate the concentration of Na2EDTA (aq) solution by rearranging the above equation:
Concentration = Moles of Na2EDTA / Volume
Concentration = (0.05 L * Concentration) / 0.025 L
Concentration = 2 * Concent
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A solution containing 250 ppm of CuSO4 5H2O (formula weight = 250) has an absorbance of 0.1 measured in 1 cm cell at 600 nm. Calculate the molar absorptivity (e) of CuSO4 5H2O in L M-1 cm-1 . When 25 mL of Na2EDTA (aq) solution is titrated against Na2EDTA (aq) solution, it consumes at 50 mL of Na2EDTA (aq) solution. Calculate the concentration of Na2EDTA (aq) solution in moles L-1 .Correct answer is '= 102 litr mol-1 cm -1'. Can you explain this answer?
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A solution containing 250 ppm of CuSO4 5H2O (formula weight = 250) has an absorbance of 0.1 measured in 1 cm cell at 600 nm. Calculate the molar absorptivity (e) of CuSO4 5H2O in L M-1 cm-1 . When 25 mL of Na2EDTA (aq) solution is titrated against Na2EDTA (aq) solution, it consumes at 50 mL of Na2EDTA (aq) solution. Calculate the concentration of Na2EDTA (aq) solution in moles L-1 .Correct answer is '= 102 litr mol-1 cm -1'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A solution containing 250 ppm of CuSO4 5H2O (formula weight = 250) has an absorbance of 0.1 measured in 1 cm cell at 600 nm. Calculate the molar absorptivity (e) of CuSO4 5H2O in L M-1 cm-1 . When 25 mL of Na2EDTA (aq) solution is titrated against Na2EDTA (aq) solution, it consumes at 50 mL of Na2EDTA (aq) solution. Calculate the concentration of Na2EDTA (aq) solution in moles L-1 .Correct answer is '= 102 litr mol-1 cm -1'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution containing 250 ppm of CuSO4 5H2O (formula weight = 250) has an absorbance of 0.1 measured in 1 cm cell at 600 nm. Calculate the molar absorptivity (e) of CuSO4 5H2O in L M-1 cm-1 . When 25 mL of Na2EDTA (aq) solution is titrated against Na2EDTA (aq) solution, it consumes at 50 mL of Na2EDTA (aq) solution. Calculate the concentration of Na2EDTA (aq) solution in moles L-1 .Correct answer is '= 102 litr mol-1 cm -1'. Can you explain this answer?.
A solution containing 250 ppm of CuSO4 5H2O (formula weight = 250) has an absorbance of 0.1 measured in 1 cm cell at 600 nm. Calculate the molar absorptivity (e) of CuSO4 5H2O in L M-1 cm-1 . When 25 mL of Na2EDTA (aq) solution is titrated against Na2EDTA (aq) solution, it consumes at 50 mL of Na2EDTA (aq) solution. Calculate the concentration of Na2EDTA (aq) solution in moles L-1 .Correct answer is '= 102 litr mol-1 cm -1'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A solution containing 250 ppm of CuSO4 5H2O (formula weight = 250) has an absorbance of 0.1 measured in 1 cm cell at 600 nm. Calculate the molar absorptivity (e) of CuSO4 5H2O in L M-1 cm-1 . When 25 mL of Na2EDTA (aq) solution is titrated against Na2EDTA (aq) solution, it consumes at 50 mL of Na2EDTA (aq) solution. Calculate the concentration of Na2EDTA (aq) solution in moles L-1 .Correct answer is '= 102 litr mol-1 cm -1'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution containing 250 ppm of CuSO4 5H2O (formula weight = 250) has an absorbance of 0.1 measured in 1 cm cell at 600 nm. Calculate the molar absorptivity (e) of CuSO4 5H2O in L M-1 cm-1 . When 25 mL of Na2EDTA (aq) solution is titrated against Na2EDTA (aq) solution, it consumes at 50 mL of Na2EDTA (aq) solution. Calculate the concentration of Na2EDTA (aq) solution in moles L-1 .Correct answer is '= 102 litr mol-1 cm -1'. Can you explain this answer?.
Solutions for A solution containing 250 ppm of CuSO4 5H2O (formula weight = 250) has an absorbance of 0.1 measured in 1 cm cell at 600 nm. Calculate the molar absorptivity (e) of CuSO4 5H2O in L M-1 cm-1 . When 25 mL of Na2EDTA (aq) solution is titrated against Na2EDTA (aq) solution, it consumes at 50 mL of Na2EDTA (aq) solution. Calculate the concentration of Na2EDTA (aq) solution in moles L-1 .Correct answer is '= 102 litr mol-1 cm -1'. Can you explain this answer? in English & in Hindi are available as part of our courses for IIT JAM.
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ample number of questions to practice A solution containing 250 ppm of CuSO4 5H2O (formula weight = 250) has an absorbance of 0.1 measured in 1 cm cell at 600 nm. Calculate the molar absorptivity (e) of CuSO4 5H2O in L M-1 cm-1 . When 25 mL of Na2EDTA (aq) solution is titrated against Na2EDTA (aq) solution, it consumes at 50 mL of Na2EDTA (aq) solution. Calculate the concentration of Na2EDTA (aq) solution in moles L-1 .Correct answer is '= 102 litr mol-1 cm -1'. Can you explain this answer? tests, examples and also practice IIT JAM tests.
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