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Sahil has a field in the shape of rectangle. The length of the field is twice its breadth. The breadth is 80 m. Find the perimeter of the field
  • a)
    360 m                       
  • b)
    480 m 
  • c)
    460 m                 
  • d)
    520 m
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Sahil has a field in the shape of rectangle. The length of the field i...
Breadth of the field = 80 m Length of the field = 2 × 80 = 160m Perimeter of the field = 2 (length + breadth) =2(160 + 80)=2 × 240 = 480m
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Most Upvoted Answer
Sahil has a field in the shape of rectangle. The length of the field i...
First, let's assign variables to the length and breadth of the field:
Let the length of the field be L.
Let the breadth of the field be B.

From the given information, we know that the breadth of the field is 80 m. So we can write:
B = 80 m

We are also given that the length of the field is twice its breadth. So we can write:
L = 2B

To find the perimeter of the field, we need to add up all the sides of the rectangle. The formula to find the perimeter of a rectangle is:
Perimeter = 2(L + B)

Substituting the values of L and B from the given information, we get:
Perimeter = 2(2B + B)
Perimeter = 2(3B)
Perimeter = 6B

Now, substitute the value of B from the given information:
Perimeter = 6(80)
Perimeter = 480 m

Therefore, the perimeter of the field is 480 m, which corresponds to option B.
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Sahil has a field in the shape of rectangle. The length of the field is twice its breadth. The breadth is 80 m. Find the perimeter of the fielda)360 mb)480 mc)460 md)520 mCorrect answer is option 'B'. Can you explain this answer?
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