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An insulated tank initially contains 0.25 kg of a gas with an internal energy of 200 kJ/kg .Additional gas with an internal energy of 300 kJ/kg and an enthalpy of 400 kJ/kg enters the tank until the total mass of gas contained is 1 kg. What is the final internal energy(in kJ/kg) of the gas in the tank? A: 250 B: 275 C: 350 D: None of the above Answer given C?
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An insulated tank initially contains 0.25 kg of a gas with an internal...
Given:
- Initial mass of gas in the tank = 0.25 kg
- Initial internal energy of the gas = 200 kJ/kg
- Additional gas enters the tank with an internal energy of 300 kJ/kg and an enthalpy of 400 kJ/kg
- Total mass of gas in the tank after addition = 1 kg

To find:
- Final internal energy of the gas in the tank

Assumptions:
- The gas is an ideal gas, and its specific heat capacity remains constant throughout the process.

Solution:
1. Let's denote the initial mass of the gas in the tank as m1, initial internal energy as u1, additional mass of gas as m2, and additional internal energy as u2.
2. The total mass of gas in the tank after addition is given as 1 kg. So, we can write the equation as:
m1 + m2 = 1 ...(1)
3. The total internal energy of the gas in the tank after addition can be calculated using the equation:
m1*u1 + m2*u2 = (m1 + m2)*uf
where uf is the final internal energy of the gas.
4. Substituting the values in the equation, we get:
0.25*200 + m2*300 = (0.25 + m2)*uf
50 + 300m2 = (0.25 + m2)*uf
5. From equation (1), we can substitute m2 = 1 - m1 in the above equation:
50 + 300(1 - m1) = (0.25 + (1 - m1))*uf
50 + 300 - 300m1 = 0.25 + 0.75 - 0.75m1 + uf
6. Simplifying the equation, we get:
300 - 300m1 = 1 + uf - 0.75m1
300 - 1 = uf - 0.75m1 + 300m1
uf = 275 + 0.25m1

Conclusion:
The final internal energy of the gas in the tank is given by uf = 275 + 0.25m1. Since we do not have the value of m1, we cannot calculate the exact value of uf. Therefore, the correct answer is D: None of the above.
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An insulated tank initially contains 0.25 kg of a gas with an internal energy of 200 kJ/kg .Additional gas with an internal energy of 300 kJ/kg and an enthalpy of 400 kJ/kg enters the tank until the total mass of gas contained is 1 kg. What is the final internal energy(in kJ/kg) of the gas in the tank? A: 250 B: 275 C: 350 D: None of the above Answer given C?
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An insulated tank initially contains 0.25 kg of a gas with an internal energy of 200 kJ/kg .Additional gas with an internal energy of 300 kJ/kg and an enthalpy of 400 kJ/kg enters the tank until the total mass of gas contained is 1 kg. What is the final internal energy(in kJ/kg) of the gas in the tank? A: 250 B: 275 C: 350 D: None of the above Answer given C? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about An insulated tank initially contains 0.25 kg of a gas with an internal energy of 200 kJ/kg .Additional gas with an internal energy of 300 kJ/kg and an enthalpy of 400 kJ/kg enters the tank until the total mass of gas contained is 1 kg. What is the final internal energy(in kJ/kg) of the gas in the tank? A: 250 B: 275 C: 350 D: None of the above Answer given C? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An insulated tank initially contains 0.25 kg of a gas with an internal energy of 200 kJ/kg .Additional gas with an internal energy of 300 kJ/kg and an enthalpy of 400 kJ/kg enters the tank until the total mass of gas contained is 1 kg. What is the final internal energy(in kJ/kg) of the gas in the tank? A: 250 B: 275 C: 350 D: None of the above Answer given C?.
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