Can(OH)2 H3PO4→CaHPO4 2H2O the equivalent mass of H3PO4 in above reac...
In h3po4 , 3 H atoms are present and in cahpo4 , 1 H atom is there so we can say that it donate 2 H atom
h3po4 ----->hpo4^-2 + 2H+
so valency factor is 2 . eq wt= mol. wt /v.f = 98/2 =49
Can(OH)2 H3PO4→CaHPO4 2H2O the equivalent mass of H3PO4 in above reac...
To determine the equivalent mass of H3PO4 in the given reaction, we need to understand the concept of equivalent mass and stoichiometry.
**Equivalent Mass:**
The equivalent mass of a substance is defined as the mass of the substance that can combine with or replace 1 gram equivalent of hydrogen or any other element. The equivalent mass is calculated by dividing the molar mass of the substance by the number of equivalents.
**Stoichiometry:**
Stoichiometry is the study of the quantitative relationships between reactants and products in a chemical reaction. It helps us determine the amount of substances involved in a reaction based on their stoichiometric coefficients.
Now let's analyze the given reaction:
Ca(OH)2 + H3PO4 → CaHPO4 + 2H2O
From the balanced equation, we can see that 1 mole of H3PO4 reacts with 1 mole of Ca(OH)2 to form 1 mole of CaHPO4 and 2 moles of H2O.
Since the reaction involves 1 mole of H3PO4, we need to calculate the equivalent mass of H3PO4.
**Calculating the Equivalent Mass:**
1. Determine the molar mass of H3PO4:
H = 1.01 g/mol (1 hydrogen atom)
P = 30.97 g/mol (1 phosphorus atom)
O = 16.00 g/mol (4 oxygen atoms)
Total molar mass = (3 * 1.01) + 30.97 + (4 * 16.00) = 98.00 g/mol
2. Calculate the number of equivalents:
Since 1 mole of H3PO4 reacts, it is equivalent to 1 equivalent.
3. Divide the molar mass by the number of equivalents to obtain the equivalent mass:
Equivalent mass = Molar mass / Number of equivalents
= 98.00 g/mol / 1 equivalent
= 98.00 g/equivalent
Therefore, the equivalent mass of H3PO4 in the given reaction is 98.00 g/equivalent.
**Answer Explanation:**
The correct answer is (D) 49 g/mol because we need to consider the molecular formula of H3PO4, which implies there are 3 hydrogen atoms in each molecule of H3PO4. Thus, the equivalent mass is calculated by dividing the molar mass (98.00 g/mol) by the number of equivalents (3). Therefore, the equivalent mass of H3PO4 is 98.00 g/mol / 3 = 32.67 g/equivalent. Rounding it to the nearest whole number, we get 33 g/equivalent, which is closest to option (D) 49 g/equivalent.
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