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Frequency of recessive allele in a population is 0.3. Number of individuals with heterozygous dominant trait in a population of 3000 will be?
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Frequency of recessive allele in a population is 0.3. Number of indivi...
Calculation of Number of Heterozygous Dominant Individuals in a Population
The frequency of the recessive allele in a population is 0.3, which means that the frequency of the dominant allele is 0.7 (since p + q = 1, where p is the frequency of the dominant allele and q is the frequency of the recessive allele).

Calculating the Frequency of Heterozygous Individuals
- The frequency of heterozygous individuals can be calculated using the formula 2pq, where p is the frequency of the dominant allele and q is the frequency of the recessive allele.
- Substituting the values, 2 x 0.7 x 0.3 = 0.42.

Calculating the Number of Heterozygous Dominant Individuals
- To find the number of heterozygous dominant individuals in a population of 3000, we multiply the frequency of heterozygous individuals by the total population size.
- 0.42 x 3000 = 1260 individuals with a heterozygous dominant trait in the population.
Therefore, in a population of 3000 individuals, there will be 1260 individuals with a heterozygous dominant trait.
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Frequency of recessive allele in a population is 0.3. Number of individuals with heterozygous dominant trait in a population of 3000 will be?
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