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How much of electrostatic energy is stored in the capacitor if the capacitor with 12pF of capacitance is connected to a 50v battery?
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Calculation of Electrostatic Energy Stored in a Capacitor:

To calculate the electrostatic energy stored in a capacitor, we need to use the formula:

E = (1/2)CV^2

where E is the electrostatic energy, C is the capacitance of the capacitor, and V is the voltage applied to the capacitor.

Given:

Capacitance of the capacitor (C) = 12 pF

Voltage applied (V) = 50 V

Using the above formula, we can calculate the electrostatic energy stored in the capacitor as follows:

E = (1/2)CV^2
E = (1/2)(12 × 10^-12 F)(50 V)^2
E = (1/2)(12 × 10^-12 F)(2500 V^2)
E = (1/2)(30 × 10^-9 J)
E = 15 × 10^-9 J
E = 15 nJ

Therefore, the electrostatic energy stored in the capacitor is 15 nJ.

Explanation:

When a voltage is applied to a capacitor, it stores electric charge, which creates an electric field between its plates. The energy stored in the capacitor is equal to the work done to charge the capacitor against this electric field. The higher the voltage applied or the larger the capacitance of the capacitor, the more energy it can store.

In this case, the capacitor has a capacitance of 12 pF and a voltage of 50 V applied to it. Using the formula for electrostatic energy stored in a capacitor, we calculated that the energy stored in the capacitor is 15 nJ.

This energy can be released when the capacitor is discharged, and it can be used in various electronic applications, such as in filters, oscillators, and power supplies.
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How much of electrostatic energy is stored in the capacitor if the capacitor with 12pF of capacitance is connected to a 50v battery?
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