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We have (n+1) white balls and (n+1) black balls. In each set the balls are numbered from 1 to (n+1). If these balls are to be arranged in a row so that two consecutive balls are of different colours, then the number of these arrangements isa)(2n+2)!b)2 x (2n+2)c)2 x (n+1)!d)2[(n+1)!]2Correct answer is option 'D'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about We have (n+1) white balls and (n+1) black balls. In each set the balls are numbered from 1 to (n+1). If these balls are to be arranged in a row so that two consecutive balls are of different colours, then the number of these arrangements isa)(2n+2)!b)2 x (2n+2)c)2 x (n+1)!d)2[(n+1)!]2Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for We have (n+1) white balls and (n+1) black balls. In each set the balls are numbered from 1 to (n+1). If these balls are to be arranged in a row so that two consecutive balls are of different colours, then the number of these arrangements isa)(2n+2)!b)2 x (2n+2)c)2 x (n+1)!d)2[(n+1)!]2Correct answer is option 'D'. Can you explain this answer?.

Solutions for We have (n+1) white balls and (n+1) black balls. In each set the balls are numbered from 1 to (n+1). If these balls are to be arranged in a row so that two consecutive balls are of different colours, then the number of these arrangements isa)(2n+2)!b)2 x (2n+2)c)2 x (n+1)!d)2[(n+1)!]2Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of We have (n+1) white balls and (n+1) black balls. In each set the balls are numbered from 1 to (n+1). If these balls are to be arranged in a row so that two consecutive balls are of different colours, then the number of these arrangements isa)(2n+2)!b)2 x (2n+2)c)2 x (n+1)!d)2[(n+1)!]2Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of We have (n+1) white balls and (n+1) black balls. In each set the balls are numbered from 1 to (n+1). If these balls are to be arranged in a row so that two consecutive balls are of different colours, then the number of these arrangements isa)(2n+2)!b)2 x (2n+2)c)2 x (n+1)!d)2[(n+1)!]2Correct answer is option 'D'. Can you explain this answer?, a detailed solution for We have (n+1) white balls and (n+1) black balls. In each set the balls are numbered from 1 to (n+1). If these balls are to be arranged in a row so that two consecutive balls are of different colours, then the number of these arrangements isa)(2n+2)!b)2 x (2n+2)c)2 x (n+1)!d)2[(n+1)!]2Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of We have (n+1) white balls and (n+1) black balls. In each set the balls are numbered from 1 to (n+1). If these balls are to be arranged in a row so that two consecutive balls are of different colours, then the number of these arrangements isa)(2n+2)!b)2 x (2n+2)c)2 x (n+1)!d)2[(n+1)!]2Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice We have (n+1) white balls and (n+1) black balls. In each set the balls are numbered from 1 to (n+1). If these balls are to be arranged in a row so that two consecutive balls are of different colours, then the number of these arrangements isa)(2n+2)!b)2 x (2n+2)c)2 x (n+1)!d)2[(n+1)!]2Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.