The number of ways in which a committee of 6 members can be formed fro...
A committee of 6 members is to formed from 8 gentlemen and 4 ladies by taking
(i) 3 lady out of 4 and 3 gentlemen out of 8
(ii) 4 lady out of 4 and 2 gentlemen out of 8
In case (i) the number of ways = 4c3 x 8c3
= 4 x 56 = 224
In case (ii) the number of ways = 4c4 x 8c2
= 1 x 28 = 28
Hence, the required number of ways = 224 + 28 = 252
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The number of ways in which a committee of 6 members can be formed fro...
To solve this problem, we can use the concept of combinations.
Step 1: Determine the number of ways to select exactly 3 ladies and 3 gentlemen for the committee.
We can choose 3 ladies out of 4 in C(4, 3) ways, which is equal to 4.
Similarly, we can choose 3 gentlemen out of 8 in C(8, 3) ways, which is equal to 56.
Therefore, the number of ways to select exactly 3 ladies and 3 gentlemen is 4 * 56 = 224.
Step 2: Determine the number of ways to select exactly 4 ladies and 2 gentlemen for the committee.
We can choose 4 ladies out of 4 in C(4, 4) ways, which is equal to 1.
Similarly, we can choose 2 gentlemen out of 8 in C(8, 2) ways, which is equal to 28.
Therefore, the number of ways to select exactly 4 ladies and 2 gentlemen is 1 * 28 = 28.
Step 3: Determine the number of ways to select exactly 5 ladies and 1 gentleman for the committee.
We can choose 5 ladies out of 4, which is not possible, so the number of ways is 0.
Step 4: Determine the number of ways to select all 6 ladies for the committee.
We can choose all 6 ladies out of 4, which is not possible, so the number of ways is 0.
Step 5: Determine the number of ways to select at least 3 ladies for the committee.
Now, we add up the results from steps 1, 2, 3, and 4.
224 + 28 + 0 + 0 = 252.
Therefore, the number of ways to form a committee of 6 members that contains at least 3 ladies is 252.
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