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Two cells of emf 1.25V , 0.75V and each of internal resistance 1Ω are connected in parallel. The effective emf will be
- a)1 V
- b)1.25 V
- c)0.5 V
- d)0.75 V
Correct answer is option 'A'. Can you explain this answer?
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Two cells of emf1.25V , 0.75V and each of internal resistance1Ω ...
The circuit diagram for the given setup is as follows:
```
____
| |
| |
_____|____|_____
| |
| |
___|___ ___|___
| | | |
| E1 |___r1____| E2 |___r2___
|_____| |_____|
```
Where, E1 and E2 are the emf of the two cells, r1 and r2 are their respective internal resistance.
To find the equivalent emf and internal resistance of the combination, we can use the following formulae:
1. Equivalent emf (Eeq) = E1 + E2
2. Equivalent internal resistance (req) = r1 + r2
Substituting the given values, we get:
1. Eeq = 1.25V + 0.75V = 2V
2. req = 1Ω + 1Ω = 2Ω
Therefore, the equivalent emf of the combination is 2V and the equivalent internal resistance is 2Ω.
```
____
| |
| |
_____|____|_____
| |
| |
___|___ ___|___
| | | |
| E1 |___r1____| E2 |___r2___
|_____| |_____|
```
Where, E1 and E2 are the emf of the two cells, r1 and r2 are their respective internal resistance.
To find the equivalent emf and internal resistance of the combination, we can use the following formulae:
1. Equivalent emf (Eeq) = E1 + E2
2. Equivalent internal resistance (req) = r1 + r2
Substituting the given values, we get:
1. Eeq = 1.25V + 0.75V = 2V
2. req = 1Ω + 1Ω = 2Ω
Therefore, the equivalent emf of the combination is 2V and the equivalent internal resistance is 2Ω.
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Two cells of emf1.25V , 0.75V and each of internal resistance1Ω are connected in parallel. The effective emf will bea)1Vb)1.25 Vc)0.5 Vd)0.75 VCorrect answer is option 'A'. Can you explain this answer? for Class 12 2026 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Two cells of emf1.25V , 0.75V and each of internal resistance1Ω are connected in parallel. The effective emf will bea)1Vb)1.25 Vc)0.5 Vd)0.75 VCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two cells of emf1.25V , 0.75V and each of internal resistance1Ω are connected in parallel. The effective emf will bea)1Vb)1.25 Vc)0.5 Vd)0.75 VCorrect answer is option 'A'. Can you explain this answer?.
Two cells of emf1.25V , 0.75V and each of internal resistance1Ω are connected in parallel. The effective emf will bea)1Vb)1.25 Vc)0.5 Vd)0.75 VCorrect answer is option 'A'. Can you explain this answer? for Class 12 2026 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Two cells of emf1.25V , 0.75V and each of internal resistance1Ω are connected in parallel. The effective emf will bea)1Vb)1.25 Vc)0.5 Vd)0.75 VCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2026 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two cells of emf1.25V , 0.75V and each of internal resistance1Ω are connected in parallel. The effective emf will bea)1Vb)1.25 Vc)0.5 Vd)0.75 VCorrect answer is option 'A'. Can you explain this answer?.
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