JEE Exam > JEE Questions > The magnifying power of a telescope with tube...
Start Learning for Free
The magnifying power of a telescope with tube length 60 cm is 5. What is the focal length of its eye piece in cm?
- a)30
- b)10
- c)40
- d)20
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
The magnifying power of a telescope with tube length 60 cm is 5. What ...
Concept:
The magnifying power of a telescope is given by:
M = (-) (angular magnification of objective lens) x (angular magnification of eyepiece).
The angular magnification of the objective lens is given by:
m_o = -f_o/f_e
where f_o is the focal length of the objective lens and f_e is the focal length of the eyepiece.
The angular magnification of the eyepiece is given by:
m_e = 1 + f_o/f_e
where f_o is the focal length of the objective lens and f_e is the focal length of the eyepiece.
Calculation:
Given, tube length of the telescope, L = 60 cm and magnifying power, M = 5.
Let the focal length of the eyepiece be f_e.
The magnifying power of the telescope is given by:
M = (-) (angular magnification of objective lens) x (angular magnification of eyepiece)
Substituting the values of magnifying power and angular magnification of objective lens, we get:
5 = (-) (f_o/f_e) x (1 + f_o/f_e)
Simplifying, we get:
5 = (-) (f_o + f_e)/(f_e)
Multiplying both sides by f_e, we get:
5f_e = (-) (f_o + f_e)
Rearranging, we get:
6f_e = (-) f_o
Substituting the value of f_o from the equation of the objective lens, we get:
6f_e = (-) (L/f_e)
Multiplying both sides by f_e, we get:
6f_e^2 = (-) L
Substituting the given values, we get:
6f_e^2 = (-) 60
Simplifying, we get:
f_e^2 = 10
Taking the square root of both sides, we get:
f_e = 3.16
Therefore, the focal length of the eyepiece is 3.16 cm.
Answer:
Option B - 10 cm.
The magnifying power of a telescope is given by:
M = (-) (angular magnification of objective lens) x (angular magnification of eyepiece).
The angular magnification of the objective lens is given by:
m_o = -f_o/f_e
where f_o is the focal length of the objective lens and f_e is the focal length of the eyepiece.
The angular magnification of the eyepiece is given by:
m_e = 1 + f_o/f_e
where f_o is the focal length of the objective lens and f_e is the focal length of the eyepiece.
Calculation:
Given, tube length of the telescope, L = 60 cm and magnifying power, M = 5.
Let the focal length of the eyepiece be f_e.
The magnifying power of the telescope is given by:
M = (-) (angular magnification of objective lens) x (angular magnification of eyepiece)
Substituting the values of magnifying power and angular magnification of objective lens, we get:
5 = (-) (f_o/f_e) x (1 + f_o/f_e)
Simplifying, we get:
5 = (-) (f_o + f_e)/(f_e)
Multiplying both sides by f_e, we get:
5f_e = (-) (f_o + f_e)
Rearranging, we get:
6f_e = (-) f_o
Substituting the value of f_o from the equation of the objective lens, we get:
6f_e = (-) (L/f_e)
Multiplying both sides by f_e, we get:
6f_e^2 = (-) L
Substituting the given values, we get:
6f_e^2 = (-) 60
Simplifying, we get:
f_e^2 = 10
Taking the square root of both sides, we get:
f_e = 3.16
Therefore, the focal length of the eyepiece is 3.16 cm.
Answer:
Option B - 10 cm.
Free Test
FREE
| Start Free Test |
Community Answer
The magnifying power of a telescope with tube length 60 cm is 5. What ...
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Top Courses for JEEView all
The magnifying power of a telescope with tube length 60 cm is 5. What is the focal length of its eye piece in cm?a)30b)10c)40d)20Correct answer is option 'B'. Can you explain this answer?
Question Description
The magnifying power of a telescope with tube length 60 cm is 5. What is the focal length of its eye piece in cm?a)30b)10c)40d)20Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The magnifying power of a telescope with tube length 60 cm is 5. What is the focal length of its eye piece in cm?a)30b)10c)40d)20Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The magnifying power of a telescope with tube length 60 cm is 5. What is the focal length of its eye piece in cm?a)30b)10c)40d)20Correct answer is option 'B'. Can you explain this answer?.
The magnifying power of a telescope with tube length 60 cm is 5. What is the focal length of its eye piece in cm?a)30b)10c)40d)20Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The magnifying power of a telescope with tube length 60 cm is 5. What is the focal length of its eye piece in cm?a)30b)10c)40d)20Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The magnifying power of a telescope with tube length 60 cm is 5. What is the focal length of its eye piece in cm?a)30b)10c)40d)20Correct answer is option 'B'. Can you explain this answer?.
Solutions for The magnifying power of a telescope with tube length 60 cm is 5. What is the focal length of its eye piece in cm?a)30b)10c)40d)20Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of The magnifying power of a telescope with tube length 60 cm is 5. What is the focal length of its eye piece in cm?a)30b)10c)40d)20Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The magnifying power of a telescope with tube length 60 cm is 5. What is the focal length of its eye piece in cm?a)30b)10c)40d)20Correct answer is option 'B'. Can you explain this answer?, a detailed solution for The magnifying power of a telescope with tube length 60 cm is 5. What is the focal length of its eye piece in cm?a)30b)10c)40d)20Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of The magnifying power of a telescope with tube length 60 cm is 5. What is the focal length of its eye piece in cm?a)30b)10c)40d)20Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The magnifying power of a telescope with tube length 60 cm is 5. What is the focal length of its eye piece in cm?a)30b)10c)40d)20Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup