JEE Exam > JEE Questions > An electron of mass me, initially at rest, mo...
Start Learning for Free
An electron of mass me , initially at rest, moves through a certain distance in a uniform electric field in time t1 .A proton of mass mp ,also initially at rest, takes time t2 to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio t1 /t2 is nearly equal to.
- a)√(me/mp)
- b)1836
- c)√(mp/me)
- d)1
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
An electron of mass me, initially at rest, moves through a certain dis...
Answer :- c
Solution :- If the acceleration is a then the distance s travelled in time t is given by
S = 1/2at^2
Therefore for electron
S = ½ a(e)t2^1
And for Electron
S = ½ a(p)t2^2
Thus, t2/t1 = [a(e)/a(p)]^1/2.......... (1)
Force on electron in an electric field E
F(e) = eE
Thus the acceleration of the electron if its mass is
a(e) = F(e)/Me => eE/Me
Similarly the acceleration of the proton
a(p) = F(e)/Mp => eE/Mp
Therefore, a(e)/a(p) = Mp/Me
Therefore, from (1)
t2/t1 =(Mp/Me)^1/2
Most Upvoted Answer
An electron of mass me, initially at rest, moves through a certain dis...
Since the electric field is uniform, the acceleration of both the electron and proton will be the same, given by:
a = F/m
where F is the force on the particle and m is its mass. The force on the particle is given by:
F = qE
where q is the charge of the particle and E is the electric field. Thus, we have:
a = qE/m
For the electron, we know that its initial velocity is zero and its final velocity is given by:
v = at1
where v is the final velocity and t1 is the time it takes for the electron to move through the distance. The distance moved by the electron is not given, but it is the same distance through which the proton moves in time t2. Thus, the distance is irrelevant for the ratio t1/t2. We can solve for t1 as:
t1 = v/a = (qE/m)e/m
where e is the charge of the electron. Similarly, for the proton, we have:
t2 = v/a = (qE/m)p/m
where p is the charge of the proton. Thus, the ratio t1/t2 is:
t1/t2 = [(qE/m)e/m]/[(qE/m)p/m] = (me/mp)
Note that the electric field cancels out, so it is not relevant to the ratio. Plugging in the masses of the electron and proton, we get:
t1/t2 = (9.11 x 10^-31 kg)/(1.67 x 10^-27 kg) = 0.0000545
Thus, the ratio t1/t2 is approximately 0.0000545.
a = F/m
where F is the force on the particle and m is its mass. The force on the particle is given by:
F = qE
where q is the charge of the particle and E is the electric field. Thus, we have:
a = qE/m
For the electron, we know that its initial velocity is zero and its final velocity is given by:
v = at1
where v is the final velocity and t1 is the time it takes for the electron to move through the distance. The distance moved by the electron is not given, but it is the same distance through which the proton moves in time t2. Thus, the distance is irrelevant for the ratio t1/t2. We can solve for t1 as:
t1 = v/a = (qE/m)e/m
where e is the charge of the electron. Similarly, for the proton, we have:
t2 = v/a = (qE/m)p/m
where p is the charge of the proton. Thus, the ratio t1/t2 is:
t1/t2 = [(qE/m)e/m]/[(qE/m)p/m] = (me/mp)
Note that the electric field cancels out, so it is not relevant to the ratio. Plugging in the masses of the electron and proton, we get:
t1/t2 = (9.11 x 10^-31 kg)/(1.67 x 10^-27 kg) = 0.0000545
Thus, the ratio t1/t2 is approximately 0.0000545.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
An electron of mass me, initially at rest, moves through a certain distance in a uniform electric field in time t1.A proton of mass mp,also initially at rest, takes time t2to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio t1/t2is nearly equal to.a)√(me/mp)b)1836c)√(mp/me)d)1Correct answer is option 'C'. Can you explain this answer?
Question Description
An electron of mass me, initially at rest, moves through a certain distance in a uniform electric field in time t1.A proton of mass mp,also initially at rest, takes time t2to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio t1/t2is nearly equal to.a)√(me/mp)b)1836c)√(mp/me)d)1Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An electron of mass me, initially at rest, moves through a certain distance in a uniform electric field in time t1.A proton of mass mp,also initially at rest, takes time t2to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio t1/t2is nearly equal to.a)√(me/mp)b)1836c)√(mp/me)d)1Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electron of mass me, initially at rest, moves through a certain distance in a uniform electric field in time t1.A proton of mass mp,also initially at rest, takes time t2to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio t1/t2is nearly equal to.a)√(me/mp)b)1836c)√(mp/me)d)1Correct answer is option 'C'. Can you explain this answer?.
An electron of mass me, initially at rest, moves through a certain distance in a uniform electric field in time t1.A proton of mass mp,also initially at rest, takes time t2to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio t1/t2is nearly equal to.a)√(me/mp)b)1836c)√(mp/me)d)1Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An electron of mass me, initially at rest, moves through a certain distance in a uniform electric field in time t1.A proton of mass mp,also initially at rest, takes time t2to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio t1/t2is nearly equal to.a)√(me/mp)b)1836c)√(mp/me)d)1Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electron of mass me, initially at rest, moves through a certain distance in a uniform electric field in time t1.A proton of mass mp,also initially at rest, takes time t2to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio t1/t2is nearly equal to.a)√(me/mp)b)1836c)√(mp/me)d)1Correct answer is option 'C'. Can you explain this answer?.
Solutions for An electron of mass me, initially at rest, moves through a certain distance in a uniform electric field in time t1.A proton of mass mp,also initially at rest, takes time t2to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio t1/t2is nearly equal to.a)√(me/mp)b)1836c)√(mp/me)d)1Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of An electron of mass me, initially at rest, moves through a certain distance in a uniform electric field in time t1.A proton of mass mp,also initially at rest, takes time t2to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio t1/t2is nearly equal to.a)√(me/mp)b)1836c)√(mp/me)d)1Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
An electron of mass me, initially at rest, moves through a certain distance in a uniform electric field in time t1.A proton of mass mp,also initially at rest, takes time t2to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio t1/t2is nearly equal to.a)√(me/mp)b)1836c)√(mp/me)d)1Correct answer is option 'C'. Can you explain this answer?, a detailed solution for An electron of mass me, initially at rest, moves through a certain distance in a uniform electric field in time t1.A proton of mass mp,also initially at rest, takes time t2to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio t1/t2is nearly equal to.a)√(me/mp)b)1836c)√(mp/me)d)1Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of An electron of mass me, initially at rest, moves through a certain distance in a uniform electric field in time t1.A proton of mass mp,also initially at rest, takes time t2to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio t1/t2is nearly equal to.a)√(me/mp)b)1836c)√(mp/me)d)1Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice An electron of mass me, initially at rest, moves through a certain distance in a uniform electric field in time t1.A proton of mass mp,also initially at rest, takes time t2to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio t1/t2is nearly equal to.a)√(me/mp)b)1836c)√(mp/me)d)1Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup