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If the roots of equation (x-1)( x-5 ) k= 0 differ by 2 then the value of k is:?
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If the roots of equation (x-1)( x-5 ) k= 0 differ by 2 then the value...
Given Equation:
(x-1)(x-5) = k

Condition Given:
The roots of the equation differ by 2.

Understanding the Roots:
The roots of a quadratic equation ax^2 + bx + c = 0 can be found using the formula x = (-b ± √(b^2 - 4ac))/2a.
In this case, the roots of the given equation (x-1)(x-5) = k can be found by setting it equal to zero and solving for x.

Finding the Roots:
(x-1)(x-5) = k
Expanding,
x^2 - 5x - x + 5 = k
x^2 - 6x + 5 = k
Setting it equal to zero,
x^2 - 6x + 5 - k = 0

Using the Quadratic Formula:
The roots of the equation x^2 - 6x + 5 - k = 0 will be x = (6 ± √(36 - 4(1)(5-k)))/2

Applying the Condition:
The roots differ by 2, so the discriminant (√(36 - 4(1)(5-k))) should equal 2.

Solving for k:
36 - 4(5-k) = 4
36 - 20 + 4k = 4
16 + 4k = 4
4k = -12
k = -3
Therefore, the value of k is -3 for the roots of the equation (x-1)(x-5) = k to differ by 2.
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If the roots of equation (x-1)( x-5 ) k= 0 differ by 2 then the value of k is:?
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