JEE Exam  >  JEE Questions  >  In a system of particles 8 kg mass is subject... Start Learning for Free
In a system of particles 8 kg mass is subjected to a force of 16 N along +ve x−axis and another 8 kg mass is subjected to a force of 8 N along +ve y−axis. The magnitude of acceleration of centre of mass and the angle made by it with x−axis are given respectively by
  • a)
    √5/2ms-2,θ=45º
  • b)
     3√5ms-2,θ=tan-1(2/3)
  • c)
    √5/2ms-2,θ=tan-1(1/2)
  • d)
     1ms-2,θ=tan-1(√3)
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
In a system of particles 8 kg mass is subjected to a force of 16 N alo...
To find the acceleration of the system of particles, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass.

The formula for acceleration is:

acceleration = net force / mass

Given that the mass of the system of particles is 8 kg and the force applied is 16 N along the x-axis, we can substitute these values into the formula:

acceleration = 16 N / 8 kg

Simplifying the equation, we have:

acceleration = 2 m/s^2

Therefore, the acceleration of the system of particles is 2 m/s^2 along the x-axis.
Free Test
Community Answer
In a system of particles 8 kg mass is subjected to a force of 16 N alo...
Option C is correct
Explore Courses for JEE exam

Similar JEE Doubts

In a system of particles 8 kg mass is subjected to a force of 16 N along+ve x−axisand another 8 kg mass is subjected to a force of 8 N along+ve y−axis. The magnitude of acceleration of centre of mass and the angle made by it withx−axisare given respectively bya)√5/2ms-2,θ=45ºb)3√5ms-2,θ=tan-1(2/3)c)√5/2ms-2,θ=tan-1(1/2)d)1ms-2,θ=tan-1(√3)Correct answer is option 'C'. Can you explain this answer?
Question Description
In a system of particles 8 kg mass is subjected to a force of 16 N along+ve x−axisand another 8 kg mass is subjected to a force of 8 N along+ve y−axis. The magnitude of acceleration of centre of mass and the angle made by it withx−axisare given respectively bya)√5/2ms-2,θ=45ºb)3√5ms-2,θ=tan-1(2/3)c)√5/2ms-2,θ=tan-1(1/2)d)1ms-2,θ=tan-1(√3)Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In a system of particles 8 kg mass is subjected to a force of 16 N along+ve x−axisand another 8 kg mass is subjected to a force of 8 N along+ve y−axis. The magnitude of acceleration of centre of mass and the angle made by it withx−axisare given respectively bya)√5/2ms-2,θ=45ºb)3√5ms-2,θ=tan-1(2/3)c)√5/2ms-2,θ=tan-1(1/2)d)1ms-2,θ=tan-1(√3)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a system of particles 8 kg mass is subjected to a force of 16 N along+ve x−axisand another 8 kg mass is subjected to a force of 8 N along+ve y−axis. The magnitude of acceleration of centre of mass and the angle made by it withx−axisare given respectively bya)√5/2ms-2,θ=45ºb)3√5ms-2,θ=tan-1(2/3)c)√5/2ms-2,θ=tan-1(1/2)d)1ms-2,θ=tan-1(√3)Correct answer is option 'C'. Can you explain this answer?.
Solutions for In a system of particles 8 kg mass is subjected to a force of 16 N along+ve x−axisand another 8 kg mass is subjected to a force of 8 N along+ve y−axis. The magnitude of acceleration of centre of mass and the angle made by it withx−axisare given respectively bya)√5/2ms-2,θ=45ºb)3√5ms-2,θ=tan-1(2/3)c)√5/2ms-2,θ=tan-1(1/2)d)1ms-2,θ=tan-1(√3)Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of In a system of particles 8 kg mass is subjected to a force of 16 N along+ve x−axisand another 8 kg mass is subjected to a force of 8 N along+ve y−axis. The magnitude of acceleration of centre of mass and the angle made by it withx−axisare given respectively bya)√5/2ms-2,θ=45ºb)3√5ms-2,θ=tan-1(2/3)c)√5/2ms-2,θ=tan-1(1/2)d)1ms-2,θ=tan-1(√3)Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of In a system of particles 8 kg mass is subjected to a force of 16 N along+ve x−axisand another 8 kg mass is subjected to a force of 8 N along+ve y−axis. The magnitude of acceleration of centre of mass and the angle made by it withx−axisare given respectively bya)√5/2ms-2,θ=45ºb)3√5ms-2,θ=tan-1(2/3)c)√5/2ms-2,θ=tan-1(1/2)d)1ms-2,θ=tan-1(√3)Correct answer is option 'C'. Can you explain this answer?, a detailed solution for In a system of particles 8 kg mass is subjected to a force of 16 N along+ve x−axisand another 8 kg mass is subjected to a force of 8 N along+ve y−axis. The magnitude of acceleration of centre of mass and the angle made by it withx−axisare given respectively bya)√5/2ms-2,θ=45ºb)3√5ms-2,θ=tan-1(2/3)c)√5/2ms-2,θ=tan-1(1/2)d)1ms-2,θ=tan-1(√3)Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of In a system of particles 8 kg mass is subjected to a force of 16 N along+ve x−axisand another 8 kg mass is subjected to a force of 8 N along+ve y−axis. The magnitude of acceleration of centre of mass and the angle made by it withx−axisare given respectively bya)√5/2ms-2,θ=45ºb)3√5ms-2,θ=tan-1(2/3)c)√5/2ms-2,θ=tan-1(1/2)d)1ms-2,θ=tan-1(√3)Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice In a system of particles 8 kg mass is subjected to a force of 16 N along+ve x−axisand another 8 kg mass is subjected to a force of 8 N along+ve y−axis. The magnitude of acceleration of centre of mass and the angle made by it withx−axisare given respectively bya)√5/2ms-2,θ=45ºb)3√5ms-2,θ=tan-1(2/3)c)√5/2ms-2,θ=tan-1(1/2)d)1ms-2,θ=tan-1(√3)Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev