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In a system of particles 8 kg mass is subjected to a force of 16 N along+ve x−axisand another 8 kg mass is subjected to a force of 8 N along+ve y−axis. The magnitude of acceleration of centre of mass and the angle made by it withx−axisare given respectively bya)√5/2ms-2,θ=45ºb)3√5ms-2,θ=tan-1(2/3)c)√5/2ms-2,θ=tan-1(1/2)d)1ms-2,θ=tan-1(√3)Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
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the JEE exam syllabus. Information about In a system of particles 8 kg mass is subjected to a force of 16 N along+ve x−axisand another 8 kg mass is subjected to a force of 8 N along+ve y−axis. The magnitude of acceleration of centre of mass and the angle made by it withx−axisare given respectively bya)√5/2ms-2,θ=45ºb)3√5ms-2,θ=tan-1(2/3)c)√5/2ms-2,θ=tan-1(1/2)d)1ms-2,θ=tan-1(√3)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for In a system of particles 8 kg mass is subjected to a force of 16 N along+ve x−axisand another 8 kg mass is subjected to a force of 8 N along+ve y−axis. The magnitude of acceleration of centre of mass and the angle made by it withx−axisare given respectively bya)√5/2ms-2,θ=45ºb)3√5ms-2,θ=tan-1(2/3)c)√5/2ms-2,θ=tan-1(1/2)d)1ms-2,θ=tan-1(√3)Correct answer is option 'C'. Can you explain this answer?.
Solutions for In a system of particles 8 kg mass is subjected to a force of 16 N along+ve x−axisand another 8 kg mass is subjected to a force of 8 N along+ve y−axis. The magnitude of acceleration of centre of mass and the angle made by it withx−axisare given respectively bya)√5/2ms-2,θ=45ºb)3√5ms-2,θ=tan-1(2/3)c)√5/2ms-2,θ=tan-1(1/2)d)1ms-2,θ=tan-1(√3)Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Here you can find the meaning of In a system of particles 8 kg mass is subjected to a force of 16 N along+ve x−axisand another 8 kg mass is subjected to a force of 8 N along+ve y−axis. The magnitude of acceleration of centre of mass and the angle made by it withx−axisare given respectively bya)√5/2ms-2,θ=45ºb)3√5ms-2,θ=tan-1(2/3)c)√5/2ms-2,θ=tan-1(1/2)d)1ms-2,θ=tan-1(√3)Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
In a system of particles 8 kg mass is subjected to a force of 16 N along+ve x−axisand another 8 kg mass is subjected to a force of 8 N along+ve y−axis. The magnitude of acceleration of centre of mass and the angle made by it withx−axisare given respectively bya)√5/2ms-2,θ=45ºb)3√5ms-2,θ=tan-1(2/3)c)√5/2ms-2,θ=tan-1(1/2)d)1ms-2,θ=tan-1(√3)Correct answer is option 'C'. Can you explain this answer?, a detailed solution for In a system of particles 8 kg mass is subjected to a force of 16 N along+ve x−axisand another 8 kg mass is subjected to a force of 8 N along+ve y−axis. The magnitude of acceleration of centre of mass and the angle made by it withx−axisare given respectively bya)√5/2ms-2,θ=45ºb)3√5ms-2,θ=tan-1(2/3)c)√5/2ms-2,θ=tan-1(1/2)d)1ms-2,θ=tan-1(√3)Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of In a system of particles 8 kg mass is subjected to a force of 16 N along+ve x−axisand another 8 kg mass is subjected to a force of 8 N along+ve y−axis. The magnitude of acceleration of centre of mass and the angle made by it withx−axisare given respectively bya)√5/2ms-2,θ=45ºb)3√5ms-2,θ=tan-1(2/3)c)√5/2ms-2,θ=tan-1(1/2)d)1ms-2,θ=tan-1(√3)Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice In a system of particles 8 kg mass is subjected to a force of 16 N along+ve x−axisand another 8 kg mass is subjected to a force of 8 N along+ve y−axis. The magnitude of acceleration of centre of mass and the angle made by it withx−axisare given respectively bya)√5/2ms-2,θ=45ºb)3√5ms-2,θ=tan-1(2/3)c)√5/2ms-2,θ=tan-1(1/2)d)1ms-2,θ=tan-1(√3)Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.