Reaction:

2-chloro cyclohexanone + sodium ethoxide + ethyl alcohol → O-ethyl-2-cyclohexenone + sodium chloride + ethanol

Explanation:

The given reaction involves the treatment of 2-chloro cyclohexanone with sodium ethoxide and ethyl alcohol. The mechanism of the reaction is explained below.

Step 1:

The sodium ethoxide is a strong nucleophile and it attacks the electrophilic carbon of 2-chloro cyclohexanone, resulting in the formation of an intermediate alkoxide.

Step 2:

The intermediate alkoxide then undergoes an elimination reaction with ethyl alcohol to form the desired product, O-ethyl-2-cyclohexenone.

Step 3:

Finally, the reaction mixture is treated with dilute hydrochloric acid to obtain the product in a pure form. Sodium chloride and ethanol are the by-products of the reaction.

Overall Reaction:

2-chloro cyclohexanone + sodium ethoxide + ethyl alcohol → O-ethyl-2-cyclohexenone + sodium chloride + ethanol

Summary:

The given reaction involves the treatment of 2-chloro cyclohexanone with sodium ethoxide and ethyl alcohol to obtain O-ethyl-2-cyclohexenone. The reaction proceeds through the formation of an intermediate alkoxide, which undergoes an elimination reaction with ethyl alcohol to form the desired product. The by-products of the reaction are sodium chloride and ethanol.